Answer:
12.5 gm left
Explanation:
30 minutes is THREE half lives
1/2^3 = 1/8th would be left
100g * 1/8 = 12.5 gm
First, we'll identify the beaker containing pure water as follows:
We'll take equal masses from each of the three beakers and measure the mass of each.
We'll then identify the density of each by using the rule : density =mass/volume
Pure water will be the liquid having density equal to 1 gm/cm^3
Then, we'll differentiate between the salt and sugar solution by measuring the conductivity of each solution. Salt solution is a good conductor while solution of sugar is a bad conductor.
First, we have to see how K2O behaves when it is dissolved in water:
K2O + H20 = 2 KOH
According to reaction K2O has base properties, so it forms a hydroxide in water.
For the reaction next relation follows:
c(KOH) : c(K2O) = 1 : 2
So,
c(KOH)= 2 x c(K2O)= 2 x 0.005 = 0.01 M = c(OH⁻)
Now we can calculate pH:
pOH= -log c(OH⁻) = -log 0.01 = 2
pH= 14-2 = 12
Answer:
The answer to your question is V2 = 18.45 l
Explanation:
Data
Volume 1 = V1 = 12.3 l
Temperature 1 = T1 = 40°K
Volume 2 = V2 = ?
Temperature 2 = T2 = 60°K
Process
To solve this problem use Charles' law
V1/T1 = V2/T2
-Solve for V2
V2 = V1T2 / T1
-Substitution
V2 = (12.3 x 60) / 40
-Simplification
V2 = 738 / 40
-Result
V2 = 18.45 l
