Ask question

Ask question

All categories

Marta_Voda [28]

3 years ago

10

What are the basic steps of the scientific method??

1 answer:

finlep [7]3 years ago

4 0

1) Make an observation
2) Come up with a question
3) Making a hypothesis
4) Testing the hypothesis
5) Analyze the conclusions
6) Draw conclusions

this is how I've always learned it in school so I'm not sure if you learned it differently.

You might be interested in

Maple syrup, which comes from the sap of maple trees, contains water and natural sugars. It's a clear, brown liquid and the suga

WITCHER [35]

Maple syrup, which comes from the sap of maple trees, contains water and natural sugars. It's a clear, brown liquid and the sugars can’t be separated byfiltration. The category is insoluble.

6 0

3 years ago

A solution is prepared by dissolving 50.0g C6H12O6 in 250g of water. What is the freezing point?

Vedmedyk [2.9K]

50.0g C6H12O6 in 250g

6 0

3 years ago

water is 11.19% hydrogen and 88.1% oxygen by mass. Lake superior contains about 1.2x10 kg of water. what mass of hydrogen is con

KonstantinChe [14]

Answer:

mass of hydrogen in lake = 11.19% of 12

= 1.3428

check if question is correct or not

Explanation:

3 0

3 years ago

Read 2 more answers

The circuit element whose purpose is to convert electrical energy into another form of energy is the _____. battery resistor fus

svetoff [14.1K]

The answer is Battery...

6 0

3 years ago

Read 2 more answers

The NaCl crystal structure consists of alternating Na⁺ and Cl⁻ ions lying next to each other in three dimensions. If the Na⁺ rad

Yuliya22 [10]

Answer : The radii of the two ions Cl⁻ ion and Na⁺ ion is, 181 and 102 pm respectively.

Explanation :

As we are given that the Na⁺ radius is 56.4% of the Cl⁻ radius.

Let us assume that the radius of Cl⁻ be, (x) pm

So, the radius of Na⁺ = $x\times \frac{56.4}{100}=(0.564x)pm$

In the crystal structure of NaCl, 2 Cl⁻ ions present at the corner and 1 Na⁺ ion present at the edge of lattice.

Thus, the edge length is equal to the sum of 2 radius of Cl⁻ ion and 2 radius of Na⁺ ion.

Given:

Distance between Na⁺ nuclei = 566 pm

Thus, the relation will be:

$2\times \text{Radius of }Cl^-+2\times \text{Radius of }Na^+=\text{Distance between }Na^+\text{ nuclei}$

$2\times x+2\times 0.564x=566$

$2x+1.128x=566$

$3.128x=566$

$x=180.9\approx 181pm$

The radius of Cl⁻ ion = (x) pm = 181 pm

The radius of Na⁺ ion = (0.564x) pm = (0.564 × 181) pm =102.084 pm ≈ 102 pm

Thus, the radii of the two ions Cl⁻ ion and Na⁺ ion is, 181 and 102 pm respectively.

4 0

3 years ago