Answer:
wait can you go more in detail i can help you because i dont understand whats going on
Osmotic pressure is the pressure that would have to be applied to a pure solvent to prevent it from passing into a given solution by osmosis.
That can be mathematical computed from the expression:
Osmotic pressure=C×R×T
Where,
C= Concentration
R=Gas constant
T=Temperature
Concentration=Number of moles of solute/Volume(L)
=0.005*1000/100
=0.05
R= 0.08206 atm L/mol K
T=25+273
=298
Osmotic pressure= 0.05×0.08206×298
=1.2 atm
<h2>Greetings!</h2>
Because 1 atm is equal to 760mm Hg, you can use the following equation to find the correct atm measurement:
atm x 760
Simply plug the values given in:
0.43 x 760 = 326.8mm Hg
<h2>Hope this helps!</h2>
I Cant Answer your question but maybe this will help
Volume Changes for Gases
Particles in a gas have more freedom of movement than they do in a liquid. According to the ideal gas law, the pressure (P) and volume (V) of a gas are mutually dependent on temperature (T) and the number of moles of gas present (n). The ideal gas equation is PV = nRT, where R is a constant known as the ideal gas constant. In SI (metric) units, the value of this constant is 8.314 joules ÷ mole - degree K.
Pressure is constant: Rearranging this equation to isolate volume, you get: V = nRT ÷ P, and if you keep the pressure and number of moles constant, you have a direct relationship between volume and temperature: ∆V = nR∆T ÷ P, where ∆V is change in volume and ∆T is change in temperature. If you start from an initial temperature T0 and pressure V0 and want to know the volume at a new temperature T1 the equation becomes:
V1 = [n • R • (T1 - T0) ÷ P] +V0
Temperature is constant: If you keep the temperature constant and allow pressure to change, this equation gives you a direct relationship between volume and pressure:
V1 = [n • R • T ÷ (P1 - P0)] + V0
Notice that the volume is larger if T1 is larger than T0 but smaller if P1 is larger than P0.
Pressure and temperature both vary: When both temperature and pressure vary, the the equation becomes:
V1 = n • R • (T1 - T0) ÷ (P1 - P0) + V0
Plug in the values for initial and final temperature and pressure and the value for initial volume to find the new volume.
