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Katyanochek1 [597]
2 years ago
6

A tree was chopped down and cut up in a local forest. The tree changed in shape.

Chemistry
2 answers:
Natasha2012 [34]2 years ago
3 0

Answer would be C, Physical Change, it's similar to crumpling up a piece of paper

ololo11 [35]2 years ago
3 0

physical change is the answer

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From top to bottom in most groups of elements atomic radii tend to
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As you go down a group on the periodic table, atomic radii tend to increase because elements with larger atomic numbers have more occupied electron levels which take up more space surrounding the nucleus.

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Which is the correct order of the celestial
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If 495 milliliters of carbon dioxide at 25°C and 101.3 kilopascals reacts with excess water, what is the theoretical yield of ca
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Answer:- 1.24 g

Solution:- The balanced equation for the formation of carbonic acid by the reaction of carbon dioxide with water is:

CO_2+H_2O\rightarrow H_2CO_3

From balanced equation, there is 1:1 mol ratio between carbon dioxide and carbonic acid. So, moles of carbonic acid will be equal to the moles of carbon dioxide used.

Moles of carbon dioxide can be calculated using ideal gas law equation as it's volume, temperature and pressure are given.

we need to convert mL to L, degree C to kelvin and kilopascals to atm.

495mL(\frac{1L}{1000mL})  = 0.495 L

25 + 273 = 298 K

101.3kPa(\frac{1atm}{101.3kPa)})

= 1 atm

Ideal gas law equation is:

PV = nRT

We want to find out the n, so let's rearrange this:

n=\frac{PV}{RT}

R is the universal gas constant and it's value is \frac{0.0821atm.L}{mol.K} .

Let's pug in the values in the equation and solve it for n.

n=\frac{1*0.495}{0.0821*298}

n = 0.02 mol

To convert the moles to grams we multiply the moles by the molar mass of carbonic acid.

Molar mass of carbonic acid = 2(1.008)+12.01+3(16.00)

= 2.016+12.01+48.00

= 62.03 gram per mol (rounded to two decimal places)

Let's multiply the moles by molar mass:

0.02mol(\frac{62.03g}{mol})

= 1.24 g

So, the theoretical yield of carbonic acid is 1.24 g.


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3 years ago
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Which of the following materials is useful for making molds because it has a low melting point?
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What is the molar solubility of agcl in 0. 30 m nacl at 25°C. ksp for agcl is 1. 77 × 10^-10.
Rzqust [24]

Molar solubility of AgCl will be  0.59 ×  10^{-10} M.

The amount of a chemical that can dissolve in one liter of a solution before reaching saturation is known as its molar solubility. This implies that the quantity of a substance it can disintegrate in a solution even before the solution becomes saturated with that particular substance is determined by its molar solubility.

A compound's molar solubility would be the measure of how many moles of such a compound must dissolve to produce one liter of saturated solution. The molar solubility unit will be mol L-1.

Calculation of molar solubility:

Given data:

M = 0.30 M

K_{sp} = 1.77 × 10^{-10}

The reaction can be written as:

AgCl ⇔ Ag^{+} + Cl^{-}

s            s         (s+0.30)

K_{sp}  = [Ag^{+} ]+ [Cl^{-}]

1.77 × 10^{-10} = s (0.30)

s = 1.77 × 10^{-10}  / 0.3

s = 0.59 ×  10^{-10} M

Therefore, molar solubility of AgCl will be  0.59 ×  10^{-10} M.

To know more about molar solubility

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