Answer:
4x-13 = 2x+9 ( i think it was exterior angle property i dont remember but its true)
so, solving that eq,
4x-2x = 9+13 (grouping variables and constants)
2x=22
x=11
also, 2x+9 and 3y+2 are on a transversal, and are supplementary angles (add up to 180°)
so, solving for x in 2x+9,
2(11)+9 = 22+9 = 31°
now, 31 + 3y+2 = 180
3y = 180 - 33
y = 147/3 = 49
(hoping you understood the calculations :)
A=h(b+c)
A/h=b+c
b=(A/h)-c
Answer: b=(A/h)-c
Y^2-9^2
(y-9)(y+9)
To see if its right:
y*y+y*9-9*y-9*9
y^2+9y-9y-81
y^2-9^2
<span>5 ,1 ,-3,-7 ? what the dickens is going on?
notice, from 5 to 1, is really -4 units,
from 1 to -3, is -4 units as well, 1 -4 = -3 and so on.
so, to get the next term's value, you simply subtract 4 from the current one, namely -4 is the "common difference".
and we also know the first term is 5, ok... then
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Answer:
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