Answer:
Explanation:
As we know that initial angular speed of the tub was zero and then it increases uniformly to 4 rev/s in t = 6.00 s
so we will have
Now when the tub will comes to rest uniformly after opening the lid in time interval of t = 15 s
then we have
Now total angular displacement of the tub is given as
so number of revolutions is given as
Answer:
Distance, d = 192 meters
Explanation:
We have,
Initial velocity of an object is 10 m/s
Acceleration of the object is 3.5 m/s²
Time, t = 8 s
We need to find the distance travelled by the object during that time. Second equation of motion gives the distance travelled by the object. It is given by :
So, the distance travelled by the object is 192 meters.
Answer:
V= 14.2m/s
Explanation:
We know that acceleration= dv/dt
So 16m/s²=dv/ dt = v dv/ds
So this wil be
Integral of 16m/s² ds [at 2,2]= integral of v dv at[ 0, v]
So 16[s (3/2)/3/2] at ( s,3) = v²/2
At s= 6m
So v² = 64/3( 6^1.5-3^1.5)
= 14.2m/s
I think the correct answer from the choices listed above is option A. <span>The equation for density is mass divided by volume. An increase in density can result from all of the following except </span><span>a decrease in mass with an increase in volume.</span>
Answer:
P = 760 torr
Explanation:
Significant figures give information on the pressure of a measurement, and is directly related to the appreciations of the instruments.
When we make several different measures, some have more significant figures than others, but the criterion that ae uses is that we must use it to have the least number of significant figures, since here is the error
In this case we have 3 significant figures so the pressure value must be
P= 759.5 torr = 760 torr
Notice that we have rounded the nine (9) since the following figure is greater than or equal to 5