Answer:
a)
b)
Explanation:
a)
The width of the central bright in this diffraction pattern is given by:
when m is a natural number.
here:
- m is 1 (to find the central bright fringe)
- D is the distance from the slit to the screen
- a is the slit wide
- λ is the wavelength
So we have:
b)
Now, if we do m=2 we can find the distance to the second minima.
Now we need to subtract these distance, to get the width of the first bright fringe :
I hope it heps you!
Answer:
Explanation:This question is simply asking you to describe the following equations:
E = hv
v = c/L
E = hc/L
where E is the energy, h is Planck's constant, v is the frequency, c is the speed of light and L is the wavelength.
By looking at the equations you should be able to tell what the relationships between energy, frequency and wavelength are. If you are having difficulty describing them, then create a table with actual values and see what happens to the energy as you increase or decrease the frequency and/or wavelength.
No that is incorrect. If the results do not support the hypothesis than the hypothesis could have been incorrect. Or there is a possibility that the experiment was not done properly. A hypothesis is an educated guess for the results of the experiment.
Answer:
The magnitude of the electric field in the second case will be 
of the electric field in the first case
Explanation:
The electric field at a distance 
< R from the center of the sphere is given by
the formula 
= 
where R is the radius of the sphere, and, Q is the charge uniformly distributed on the sphere.
It is given that the same charge Q is distributed uniformly throughout a sphere of radius 2R and we have to find the electric field at same distance from the center.
In the second case the electric field will be given by
= 
Therefore the magnitude of the electric field in the second case will be of the electric field in the first case.
Answer:
P = 25299.75 watts
Since 80km/h is the average speed of 92km/h and 68km/h, the power (in watts) is needed to keep the car traveling at a constant 80 km/h is P = 25299.75 watts
Explanation:
Given;
Mass of car m = 1280kg
initial speed v1 = 92km/h = 92×1000/3600 m/s= 25.56m/s
Final speed v2 = 68km/h = 68×1000/3600 m/s= 18.89m/s
time taken t = 7.5s
Change in the kinetic energy of the car within that period;
∆K.E = 1/2 ×mv1^2 - 1/2 × mv2^2
∆K.E = 0.5m(v1^2 -v2^2)
Substituting the values, we have;
∆K.E = 0.5×1280(25.56^2 - 18.89^2)
∆K.E = 189748.16J
Power used during this Change;
Power P = ∆K.E/t
Substituting the values;
P = 189748.16/7.5
P = 25299.75 watts
Since 80km/h is the average speed of 92km/h and 68km/h, the power (in watts) is needed to keep the car traveling at a constant 80 km/h is P = 25299.75 watts
