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RUDIKE [14]
3 years ago
15

According to the conservation of momentum, if a small football player collides with a much larger football player, which of the

following statements will be true? a The larger football player will move, but because of his larger mass, his velocity will be much slower than the smaller player b The smaller football player will be stopped completely, his mass being not enough to move the larger one c The larger football player will have to start moving towards the smaller one as it collides if there is to be any effect d The smaller football player will experience a larger force than the larger football player
Physics
1 answer:
Virty [35]3 years ago
8 0

Answer:

a The larger football player will move, but because of his larger mass, his velocity will be much slower than the smaller player

Explanation:

When the collision takes two equal and opposite forces are created at the point of collision . The force created on the bigger mass will force it to accelerate and the force on moving smaller mass will force it to slow down .

Because of bigger mass , acceleration on bigger mass will be less and hence its velocity will be less .

Hence option a is the right answer.

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A man pushes a 60.8 kg crate across a rough surface with an applied force of 125 N and at a CONSTANT SPEED.
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Answer: Colby we both dumb if we need brainly lol

Explanation:

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3 years ago
The horizontal beam in Fig. E11.14 weighs 190 N, and its center of gravity is at its center. Find (a) the tension in the cable a
grandymaker [24]

Answer:

(a). The tension in the cable is 658.33 N.

(b). The horizontal components of the force exerted on the beam at the wall is 526.66 N.

(c). The vertical components of the force exerted on the beam at the wall is 95.002 N.

Explanation:

Given that,

Weight of beam= 190 N

Here, The center of gravity is at its center

According to figure,

The angle is

\sin\theta=\dfrac{3}{5}

The horizontal component is

T_{x}=T\cos\theta

The vertical component is

T_{y}=T\sin\theta

(a). We need to calculate the tension in the cable

Using formula of net torque acting on the pivot

\sum\tau=F_{b}\times r+F_{w}\times r'-T\sin \theta\times r'

Put the value into the formula

0=190\times2+300\times 4-T\sin\theta\times 4

T\sin\theta\times 4=380+1200

T=\dfrac{1580\times5}{3\times 4}

T=658.33\ N

(b). We need to calculate the horizontal components of the force exerted on the beam at the wall

Using formula of horizontal component

F_{x}=T\cos\theta

Put the value into the formula

F_{x}=658.33\times\dfrac{4}{5}

F_{x}=526.66\ N

(c). We need to calculate the vertical components of the force exerted on the beam at the wall

Using formula of vertical component

F_{y}=F_{b}+F_{w}-T\sin\theta

Put the value into the formula

F_{y}=190+300-658.33\times\dfrac{3}{5}

F_{y}=95.002\ N

Hence, (a). The tension in the cable is 658.33 N.

(b). The horizontal components of the force exerted on the beam at the wall is 526.66 N.

(c). The vertical components of the force exerted on the beam at the wall is 95.002 N.

3 0
3 years ago
1) A person having a mass of 59.1 kg stands before a flight of 30 stairs each of which is 25.0 cm high. He runs up 20 stairs, tu
poizon [28]

Answer:

P = 147,75 W

Explanation:

A man whose mass is 59.1kg climbs up 30 steps of a stair each step is 25 cm high

Height at 30 steps , h=30×2.5=  7.5 m

Change in potential energy , =mgh=59.1×10×7.5 = 4432.5 J

So, Work done by the man , W= 4432.5J

Power used , P= \frac{W}{T}

P = 4432.5 /30

P = 147,75 W

Solve any question of Work, Energy and Power with:-

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A dog exerts a force of 30N to move a wagon 2m in 5s. What is the power of the dog
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Explanation:

power=f×v. recall= distances/ time

= f× d/t

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What best describes a lens galaxy
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