Question

A drag racer starts from rest and accelerates at a constant 16.0m/s^2 until it reachs its top spees of 407km/hr. how far does it travel during this acceleration?

Answer 1

Answer:

Distance, s = 399.42 m/s

Explanation:

It is given that,

Initial velocity of drag racer, u = 0

Final velocity of drag racer, v = 407 km/hr = 113.056 m/s

Acceleration, $a=16\ m/s^2$

Third equation of motion is :

$v^2-u^2=2as$

s is the distance traveled

$s=\dfrac{v^2-u^2}{2a}$

$s=\dfrac{v^2}{2a}$

$s=\dfrac{(113.056)^2}{2\times 16}$

s = 399.42 m/s

So, the distance traveled during this acceleration is 399.42 m/s. Hence, this is the required solution.