Moles = mass/molar mass, so n(C2H6O)= 16.0 / (12+12+(1x6)+16)
=0.348 (to correct sig figs)
Answer:
101.56 of H₂O
Explanation:
The balanced equation for the reaction is given below:
CH₄ + 2O₂ —> CO₂ + 2H₂O
Next, we shall determine the mass of CH₄ that reacted and the mass of H₂O produced from the balanced equation. This is illustrated below:
Molar mass of CH₄ = 12 + (4×1.01)
= 12 + 4.04
= 16.04 g/mol
Mass of CH₄ from the balanced equation = 1 × 16.04 = 16.04 g
Molar mass of H₂O = (2×1.01) + 16
= 2.02 + 16
= 18.02 g/mol
Mass of H₂O from the balanced equation = 2 × 18.02 = 36.04g
SUMMARY:
From the balanced equation above,
16.04 g of CH₄ reacted to produce 36.04 g of H₂O.
Finally, we shall determine the mass of water, H₂O produced by the reaction of 45.2 g of methane, CH₄. This can be obtained as illustrated below:
From the balanced equation above,
16.04 g of CH₄ reacted to produce 36.04 g of H₂O.
Therefore 45.2 g of CH₄ will react to produce = (45.2 × 36.04)/16.04 = 101.56 g of H₂O.
Thus, 101.56 of H₂O were obtained.
Answer:
It would be higher than expected.
Explanation:
Respiration quotient (RQ) may be defined as the quantity used for the representation of the basal metabolic rate. This mainly depends on the amount of the carbon dioxide.
The respiratory quotient represents the ratio of carbon dioxide eliminated with the amount of the oxygen consumed. During stress condition, the oxygen consumption of our body increase and more carbon dioxide is exhale out from the body. This will increase the RQ.
Thus, the answer is RQ will be higher than expected.
The moles of Al that is needed to react with 6.34 moles of Fe3O4 is 16.9 moles
<u><em> Explanation</em></u>
<em> </em>8 Al+ 3Fe3O4 → 4 Al2O3 + 9Fe
use of mole ratio of Al: fe3O4 to calculate the moles of Al
The mole ratio of Fe3O4 : Al is 8:3 therefore the moles of Al =
6.34 moles x8/3 = 16.9 moles
