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Vladimir [108]
3 years ago
7

Solve the given inequality. Describe the solution set using the set-builder or interval notation. Then, graph the solution set o

n a number line. m+4≥6

Mathematics
1 answer:
Nat2105 [25]3 years ago
7 0

Answer:

m is greater in the end so the darker line should go right as it's increasing and starting from the 2

Step-by-step explanation:

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ONLY answer if yk it i’m giving best answer brainliest!!
S_A_V [24]

Answer:

-x^4-10x+1/10

Step-by-step explanation:

standard form goes from biggest power to smallest power

3 0
3 years ago
Read 2 more answers
PLEASE ANSWER HONESTLY (PLEASE BE HELPFULL I HAVE BEEN STUCK ON THIS PROBLEM) WILL MARK BRANIEST IF CORRECT. (no links my comput
tankabanditka [31]

Answer:

a^2+b^2=c^2 look below

Step-by-step explanation:

Count the squares so

3^2+4^2=5^2

3*3=9

4*4=16

5*5=25

9+16=25 and it does check out

this should help if u need more explanation ill be more then happy to explain to you

7 0
3 years ago
Micheal is 5 years older than Rui Feng and Vishal is thrice as old as Micheal if Rui Feng is p years old, find i) Michael's pres
Kitty [74]

Answer:

Michael's present age = p + 5

Michael's present age = 3p + 15

Sum of there ages 6 year age = 5p + 38

Sum of there ages 3 year ago = 5p - 11

Step-by-step explanation:

Assume;

Age of Rui Feng = x

Age of Micheal = x + 5

Age if Vishal = 3[x+5]

Given:

Age of Rui Feng = P

Computation:

Michael's present age = Age of Rui Feng + 5

Michael's present age = p + 5

Vishal's present age = 3[p + 5]

Michael's present age = 3p + 15

Sum of there ages 6 year age = [p + 6] + [p + 5 + 6] + 3[p + 5] + 6

Sum of there ages 6 year age = 5p + 38

Sum of there ages 3 year ago = [p - 3] + [p + 5 - 3] + 3[p + 5] - 3

Sum of there ages 3 year ago = 5p - 11

8 0
2 years ago
Need help with all And have to show work
kari74 [83]
Altho' I can easily guess what you're supposed to do here, I must point out that you haven't included the instructions for this problem.

I'll help you by example.  Let's look at the first problem:

"Evaluate  6(z-1) at z-4."

Due to "order of operations" rules, we must do the work inside the parentheses FIRST.  Replace the z inside (z-1) with "-4".  We obtain

6(-4-1) = 6(-5) = -30 (answer.)

Your turn.  Try the next one.  If it's unclear, as questions.
8 0
3 years ago
Use base ten blocks to solve 53/4
Crazy boy [7]
if you have base ten blocks you can figure out the answer
6 0
3 years ago
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