Answer:
Centripetal Acceleration = 2.701 m/s²
Explanation:
Given:
Starting from rest so initial angular velocity ωi = 0 rad/s
Final angular velocity ωf= 78 rev/min =78 × 2π /60 rad/s = 8.168 rad/s
Radius of Rim =d/2 =12/6= 6 in = 6× 2.54 cm =15.24 cm = 0.1524 m
angular acceleration α = (ωf - ωi)/t = (8.168 rad/s - 0 rad/s)/2.91 s
α =2.807 rad/s²
now to find angular velocity at 1.5 s we have
ω = α × t = 2.807 rad/s² × 1.5 s = 4.210 rad/s
so centripetal acceleration ac = ω² r = (4.210 rad/s)² × 0.1524 m
ac= 2.701 m/s²
Answer
given,
Distance for decibel reading
r₁ = 13 m
r₂ = 24 m
When the engineer is at r₁ reading is β₁ = 101 dB
now, Calculating the Intensity at r₁
Using formula
I₀ = 10⁻¹² W/m²
now inserting the given values
I = 0.01258 W/m²
now, calculating power at r₁
P₁ = I₁ A₁
P₁ = 0.01258 x 4 π r²
P₁ = 0.01258 x 4 π x 13²
P₁ = 26.72 W
Answer:
where m < M is delivered to the space station. Soon after, the space station's orbit is adjusted so that it is 50 km ...
Answer:
There will be 2 beta particles released in the decay
Explanation:
See the image below