Answer:
For a non-relativistic limit, we should expect our usual intuition regarding the accelerating charges to hold, and a falling charge should radiate with an acceleration. On the other hand, in general relativity a falling charge simply follows a geodesic of the earth's curved space-time; it is not accelerating relative to freely falling frames, and so is not accelerating in a meaningful sense.
The magnetic field strength of a very long current-carrying wire is proportional to the inverse of the distance from the wire. The farther you go from the wire, the weaker the magnetic field becomes.
B ∝ 1/d
B = magnetic field strength, d = distance from wire
Calculate the scaling factor for d required to change B from 25μT to 2.8μT:
2.8μT/25μT = 1/k
k = 8.9
You must go to a distance of 8.9d to observe a magnetic field strength of 2.8μT
option a
perpendicular to diameter
Explanation:
- perpendicular to diameter
- hemisphere is uniformly charge positively
- the diameter is 0 at the center
- electric property associated with each point in space
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Refer to the diagram shown below
Given:
m = 2.8 kg, the mass of the bucket
a =3.1 m/s², the acceleration of the bucket
Therefore
W = 2.8*9.8 = 27.44 N, the weight of the bucket.
Let T = the tension in the rope.
From the free body diagram, the net force accelerating the bucket is
T - W = m*a
That is,
T = W + m*a
= 27.44 + 2.8*3.1 N
= 36.12 N
Answer: d. 36.1 N