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evablogger [386]
3 years ago
11

Explain the conditions through which friction can be increased.​

Physics
2 answers:
Rufina [12.5K]3 years ago
8 0

Answer:

Friction can be increased the longer two objects are rubbed together, since the longer they are rubbed is the more heat produced.

Explanation:

Thepotemich [5.8K]3 years ago
6 0

Answer:

walking, car moving

Explanation:

basically anything with two surfaces pressing together ig

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Erwin Schrödinger developed the quantum model of the atom. What scientific knowledge was necessary for Schrödinger’s work?
Vikki [24]

The scientific knowledge was necessary for Schrödinger’s work is the discoverd of electron.

<h3>What is electron and how was it discovered?</h3>

Thomson carried out new experiments that led him to conclude that cathode rays were formed by particles that have a negative charge. Later, Thomson proved that these rays were deflected by applying an electric field. Thus, these particles were called electrons.

The discovery of the electron allowed Schrodinger to explain quantum models that are based on how electrons behave.

See more about quantum model at brainly.com/question/13352063

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6 0
1 year ago
NEED HELP ASAPPPPPPP!
AlekseyPX

Answer:

Changeable. Answer is c

Explanation:

3 0
3 years ago
Read 2 more answers
The flow of electrons through a wire or any conductor is called____.
Karo-lina-s [1.5K]
Electricity. Ruler. 69. N.
5 0
2 years ago
if a car that is 100 feet in front of you on route 70 west slams on the brakes while you are traveling 65 miles per hour (95 fee
fenix001 [56]

Answer:

t = 1.05 s

Explanation:

Given,

The distance between your vehicle and car, 100 ft

The constant speed of your vehicle, u = 95 ft/s

Since, the velocity is constant, a =0

If the car stopped suddenly, time left for you to hit the brake, t = ?

Using the second equation of motion,

                           S = ut + ½ at²

Substituting the given values in the equation

                           100 = 95 x t

                             t = 100/95

                               = 1.05 s

Hence, the time left for you to hit the brakes and stop before rear ending them, t = 1.05 s

5 0
2 years ago
The force required to stretch a Hooke’s-law spring varies from 0 N to 63.5 N as we stretch the spring by moving one end 5.31 cm
Alika [10]

Answer:

Force constant will be 1195.85 N/m

Work done will be 1.6859 J

Explanation:

We have given the force,  F = 63.5 N

Spring is stretched by 5.31 cm

So x = 0.0531 m

Force is given , F = 63.5 N

We know that force is given by F=kx

So 63.5=k\times 0.0531

k = 1195.85 N/m

Now we have to find the work done

We know that work done is given by

W=\frac{1}{2}kx^2=\frac{1}{2}\times 1195.85\times 0.0531^2=1.6859J

8 0
3 years ago
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