Find moles:
<span>36.0 g of glucose divided by 180 g/mol = 0.200 moles of glucose </span>
<span>find molarity: </span>
<span>0.200 moles of glucose / 2 litres = 0.100 Molar solution </span>
Answer:
(1/2)(1.62) t^2 = 1.4
That will give you the time, t
Explanation:
hope this helps(✿◡‿◡)
Answer:
Q = -18118.5KJ
W = -18118.5KJ
∆U = 0
∆H = 0
∆S = -60.80KJ/KgK
Explanation:
W = RTln(P1/P2)
P1 = 1bar = 100KN/m^2, P2 = 1500bar = 1500×100 = 150000KN/m^2, T = 23°C = 23 + 273K = 298K
W = 8.314×298ln(100/150000) = 8.314×298×-7.313 = -18118.5KJ ( work is negative because the isothermal process involves compression)
∆U = Cv(T2 - T1)
For an isothermal process, temperature is constant, so T2 = T1
∆U = Cv(T1 - T1) = Cv × 0 = 0
Q = ∆U + W = 0 + (-18118.5) = 0 - 18118.5 = -18118.5KJ
∆H = Cp(T2 - T1)
T2 = T1
∆H = Cp(T1 - T1) = Cp × 0 = 0
∆S = Q/T
Mass of water = 1kg
Heat transferred (Q) per kilogram of water = -18118.5KJ/Kg
∆S = (-18118.5KJ/Kg)/298K = -60.80KJ/KgK
Answer:
From highest to lowest:
butanol: 117.7 degree Celsius
butanone: 79.64 degree Celsius
diethyl ether: 34.6 degree Celsius
n-butane: -0.4 degree Celsius
The answer is: <span>Light strikes a beautiful white perch under water. This light is reflected back to your eyes allowing you to see the fish. As the light left the water it changes speed causing the light to bend away from the normal.
Hope this helps!
(got answer from </span>https://quizlet.com/5474123/chapter-13-light-flash-cards/ if you need more help)
