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Molodets [167]
3 years ago
10

3. There are about 7 billion (7.0x10') people on earth. If we divided the dollar amount from

Chemistry
1 answer:
Harman [31]3 years ago
6 0

Answer: i dont know it

Explanation:

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What trend in atomic radius do u see as you go a group family on the periodic table?
exis [7]
Atomic radius increases down a group
7 0
3 years ago
Read 2 more answers
Gold cylinder has a mass of 75 g and a specific heat of 0.129J/G degrees Celsius it is heated to 65°C and then put in 500 g of w
nadezda [96]
<h3>Answer:</h3>

89.88° C

<h3>Explanation:</h3>

<u>We are given;</u>

  • Mass of gold cylinder as 75 g
  • specific heat of gold is 0.129 J/g°C
  • Initial temperature of gold cylinder is 65°C
  • Mass of water is 500 g
  • Initial temperature of water is 90 °C

We are required to calculate the final temperature;

  • We know that Quantity of heat is given by the product of mass, specific heat capacity and change in temperature.
  • That is, Q = m × c × ΔT
<h3>Step 1: Calculate the quantity of heat absorbed by the Gold cylinder</h3>

Assuming the final temperature is X° C

Then; ΔT = (X-65)°C

Therefore;

Q = 75 g × 0.129 J/g°C × (X-65)°C

   = 9.675X - 628.875 Joules

<h3>Step 2: Calculate the quantity of heat released by water</h3>

Taking the final temperature as X° C

Change in temperature, ΔT = (90 - X)° C

Specific heat capacity of water is 4.184 J/g°C

Therefore;

Q = 500 g × 4.184 J/g°C × (90 - X)° C

  = 188,280 -2092X joules

<h3>Step 3: Calculate the final temperature, X°C</h3>

we know that the heat gained by gold cylinder is equal to the heat released by water.

9.675X - 628.875 Joules = 188,280 -2092X joules

2101.675 X = 188908.875

              X = 89.88° C

Thus, the final temperature is 89.88° C

3 0
3 years ago
Identify the type of interactions involved in each of the following processes taking place during the dissolution of sodium chlo
icang [17]

Answer:

A. Interactions between the ions of sodium chloride (solute-solute interactions).

B. Interactions involving dipole-dipole attractions (solvent-solvent interactions).

C. Interactions formed during hydration (solute-solvent interactions).

D. Interactions involving ion-ion attractions (solute-solute interactions).

E. Interactions associated with an exothermic process during the dissolution of sodium chloride (solute-solvent interactions).

F. Interactions between the water molecules (solvent-solvent interactions).

G. Interactions formed between the sodium ions and the oxygen atoms of water molecules (solute-solvent interactions).

Explanation:

The solution process takes place in three distinct  steps:  

  • Step 1 is the <u>separation of solvent molecules. </u>
  • Step 2 entails the <u>separation of solute molecules.</u>

These steps require energy input to break attractive intermolecular forces; therefore, <u>they are endothermic</u>.  

  • Step 3 refers to the <u>mixing of solvent and solute molecules.</u> This process can be <u>exothermic or endothermic</u>.

If the solute-solvent attraction is stronger than the solvent-solvent attraction and  solute-solute attraction, the solution process is favorable, or exothermic (ΔHsoln <  0).  If the solute-solvent interaction is weaker than the solvent-solvent and solute-solute  interactions, then the solution process is endothermic (ΔHsoln > 0).  

In the dissolution of sodium chloride, this process is exothermic.

3 0
3 years ago
In a particular mass of kau(cn)2, there are 6.66 × 1020 atoms of gold. What is the total number of atoms in this sample?
Vinvika [58]

Total number of atoms in the sample is the sum of number of atoms of all the elements present in the sample.

Number of gold, Au atoms in KAu(CN)_2 = 6.66\times 10^{20} atoms     (given)

From the formula of compound that is KAu(CN)_2 it is clear that the number of potassium and gold are same whereas those of carbon and nitrogen are 2 times of them.

So, the number of atoms of each element is:

Number of potassium, K atoms in KAu(CN)_2 = 6.66\times 10^{20} atoms    

Number of carbon, C atoms in KAu(CN)_2 = 2\times6.66\times 10^{20} atoms = 13.32\times 10^{20}

Number of nitrogen, N atoms in KAu(CN)_2 = 2\times6.66\times 10^{20} atoms = 13.32\times 10^{20}

Total number of atoms in KAu(CN)_2 = Number of gold, Au atoms+Number of potassium, K atoms +Number of carbon, C atoms + Number of nitrogen, N atoms

Total number of atoms in KAu(CN)_2 = 6.66\times 10^{20}+6.66\times 10^{20}+13.32\times 10^{20}+13.32\times 10^{20}

Total number of atoms in KAu(CN)_2 = 39.96\times 10^{20} atoms

Hence, the total number of atoms in KAu(CN)_2 is 3.996\times 10^{21} atoms.

7 0
3 years ago
What term is used to describe a testable modle
PilotLPTM [1.2K]
Well i think the answer to that is theory
3 0
4 years ago
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