Answer:
8.8g of Al are necessaries
Explanation:
Based on the reaction, 2 moles of Al are required to produce 3 moles of hydrogen gas.
To solve this question we must find the moles of H2 in 11L at STP using PV = nRT. With these moles we can find the moles of Al required and its mass as follows:
<em>Moles H2:</em>
PV = nRT; PV/RT = n
<em>Where P is pressure = 1atm at STP; V is volume = 11L; R is gas constant = 0.082atmL/molK and T is absolute temperature = 273.15K at STP</em>
Replacing:
1atm*11L/0.082atmL/molK*273.15K = n
n = 0.491 moles of H2 must be produced
<em />
<em>Moles Al:</em>
0.491 moles of H2 * (2mol Al / 3mol H2) = 0.327moles of Al are required
<em />
<em>Mass Al -Molar mass: 26.98g/mol-:</em>
0.327moles of Al * (26.98g / mol) = 8.8g of Al are necessaries
The answer is mean,mode and median
Answer:
The correct option is;
Placing one drop of food coloring in a cup with 60 ml of water at 10°, placing one drop of food coloring in a second cup with 60 ml of water at 40°C
Explanation:
The experimental setup that would allow the student investigate the connection between kinetic energy and temperature should be made up of the following characteristics
1) The constant terms for the experiment should be defined, which in this case are
a) The volume of the water which is 60 ml in both subjects of the experiment
2) The definition of the variable that produces the effect that is being monitored, which is the use of the different temperatures in the two experimental subjects
3)The environmental limits of the experiment, which is the water and the food coloring used