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Cloud [144]
3 years ago
8

HELP! What property is not used to separate a mixture ?

Chemistry
2 answers:
andre [41]3 years ago
7 0
I believe it’s conductivity
Gwar [14]3 years ago
4 0

Answer:

Mixtures can be physically separated by using methods that use differences in physical properties to separate the components of the mixture, such as evaporation, distillation, filtration and chromatography so probably conductity

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What volume of 24% trichloroacetic acid (tca) is needed to prepare eight 3 ounce bottles of 10% tca solution?
Sever21 [200]

Answer:

295.7 mL of 24% trichloroacetic acid (tca) is needed .

Explanation:

Let the volume of 24% trichloroacetic acid solution be x

Volume of required 10% trichloroacetic acid solution =8 bottles of 3 ounces

= 24 ounces = 709.68 mL

(1 ounces =  29.57 mL)

Amount of trichloroacetic acid in 24% solution of x volume of solution will be equal to amount of trichloroacetic acid in 10% solution of volume 709.68 mL.

x\times \frac{24}{100}=709.68 mL\times \frac{10}{100}

x = 295.7 mL

295.7 mL of 24% trichloroacetic acid (tca) is needed .

6 0
3 years ago
How long does it take for a purple stem plant to grow
Gala2k [10]
I couldn't really find anything about the growth time but it does say that it could remain viable in soil for up to 40 years

4 0
4 years ago
A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 64.0 mL of 0.0600 M EDTA . Titration of the excess unreacted EDTA req
tigry1 [53]

Answer:

the concentration of Cd^{2+}  in the original solution= 0.0088 M

the concentration of Mn^{2+} in the original solution = 0.058 M

Explanation:

Given that:

The volume of the sample  containing Cd2+ and Mn2+ =  50.0 mL; &

was treated with 64.0 mL of 0.0600 M EDTA

Titration of the excess unreacted EDTA required 16.1 mL of 0.0310 M Ca2+

i.e the strength of the Ca2+ = 0.0310 M

Titration of the newly freed EDTA required 14.2 mL of 0.0310 M Ca2+

To determine the concentrations of Cd2+ and Mn2+ in the original solution; we have the following :

Volume of newly freed EDTA = \frac{Volume\ of \ Ca^{2+}* Sample \ of \ strength }{Strength \ of EDTA}

= \frac{14.2*0.0310}{0.0600}

= 7.3367 mL

concentration of  Cd^{2+} = \frac{volume \ of \  newly  \ freed \ EDTA * strength \ of \ EDTA }{volume \ of \ sample}

= \frac{7.3367*0.0600}{50}

= 0.0088 M

Thus the concentration of Cd^{2+} in the original solution = 0.0088 M

Volume of excess unreacted EDTA = \frac{volume \ of \ Ca^{2+} \ * strength \ of Ca^{2+} }{Strength \ of \ EDTA}

= \frac{16.1*0.0310}{0.0600}

= 8.318 mL

Volume of EDTA required for sample containing Cd^{2+}   and  Mn^{2+}  = (64.0 - 8.318) mL

= 55.682 mL

Volume of EDTA required for Mn^{2+}  = Volume of EDTA required for

                                                                sample containing  Cd^{2+}   and  

                                                             Mn^{2+} --  Volume of newly freed EDTA

Volume of EDTA required for Mn^{2+}  = 55.682 - 7.3367

= 48.3453 mL

Concentration  of Mn^{2+} = \frac{Volume \ of EDTA \ required \ for Mn^{2+} * strength \ of \ EDTA}{volume \ of \ sample}

Concentration  of Mn^{2+} =  \frac{48.3453*0.0600}{50}

Concentration  of Mn^{2+}  in the original solution=   0.058 M

Thus the concentration of Mn^{2+} = 0.058 M

6 0
3 years ago
Which of the following statements is true?
Darya [45]
B. The nucleus of an atom contains protons and neutrons.
7 0
3 years ago
Read 2 more answers
Many carboxylic acids are much better known by their common names than by their systematic names. 2-Hydroxypropanoic acid (bette
sdas [7]

Answer:

  • CH₃ - CH - COOH

                  |

                  OH

  • The developed structural formula is also attached.

Explanation:

The IUPAC name, <em>2-hydroxypropanoic acid</em>, lets you predict the structural formula for <em>lactic acid</em>.

  • <em>2-hydroxy</em> means that there is a OH functional group attached to the second carbon atom of the chain.

  • <em>Propan</em> prefix means that the molecule has 3 carbon atoms.

  • <em>oic</em> suffix means that it is a carboxylic acid, this is it contains the COOH functional group.

Hence, in conclusion the structural form of lactic acid is:

  • C³H₃ - C²H - C¹OOH

                   |

                   OH

I used the superscripts just to show the number of the carbon atom in the chain.

The formal structural formula does not contain such superscripts it is just:

  • CH₃ - CH - COOH

                  |

                  OH

A more developed structural formula will show the distribution of the atoms in the space. I have also attached a picture with the developes structural formula.

3 0
3 years ago
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