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Mrrafil [7]
4 years ago
13

What particle is emitted in the radioactive decay 2714si→2713al?

Chemistry
2 answers:
olganol [36]4 years ago
6 0
The particle emitted in the chemical equation given above is a positron. The equation is a classical example of a beta plus decay in which a proton is converted to a neutron with an emission of a positron.
rjkz [21]4 years ago
6 0

Answer:

The radioactive decay that occur is the Beta plus decay(β+) and the particles that is emitted in the radioactive decay is the positron or positive electron

Explanation:

when Radioactivity occurs the matter that exhibit such characteristics emits energy and sub atomic particles in a spontaneous manner.  Radioactivity decay  usually occur in element with an unstable nuclei  . The element decompose or decay either rapidly or very slowly into a stable nuclei. In other words radioactivity decay occur in the nucleus if their is limited binding energy to hold the positive proton and neutral neutron to it nucleus. The rate at which this radioactive matter decay is known as the half life. Half life is the time required for one half of the quantity of the isotope to decay. Radioactivity decay occurs in three main form namely the alpha decay, beta decay and the gamma rays. Base on the question the radioactive decay that occur is the beta decay , to be specific it exhibit the beta plus decay.

In a Beta decay the unstable nucleon in the nucleus loses a nucleon to form a stable nucleus . The two type of beta decay are beta minus decay and beta plus decay . The beta minus decay occurs where the nucleus has numerous neutrons.

Beta plus decay occur where the nucleus has numerous protons and usually unstable . This kind of radioactive decay a proton in the nucleus is loss and converted to a neutron, positive electron(positron) and a neutrino. The reaction above is an example of a beta plus decay . The particles emitted here is the positron

27  14Si  →  27  13Al  +  e+   +  v  

From the decay reaction note the number 27 is super-scripted and the number 13 and 14 is sub-scripted.

v  =  neutrino

e + = positive electron

27  13Al = Resulting nucleus after decay

Notice the silicon proton reduced to form an aluminium nucleus.  

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