Answer:
Vol concentrated HCl needed = 1.73 ml
Explanation:
Prep 550 ml of HCl(aq) solution with pH = 1.60 at 25°C using 8M stock concentrate.
[HCl] = [H⁺] = 10⁻¹°⁶⁰M = 0.0251M HCl(aq)
Molarity Concentrate x Volume Concentrate = Molarity Dilute x Volume Dilute
8M x Vol Conc. = 0.0251M x 550ml
Vol Conc needed = 0.0251M x 550 ml / 8M = 1.73 ml of concentrate
Mixing => to the quantity of water in the mixing flask transfer 1.73 ml of the 8M HCl concentrate solution and dilute up to but not to exceed the calibration mark on the mixing flask.
Answer:
The answer is "3.57 and 0.07".
Explanation:
Using the slop formula:
Given:
length path 
from calibration it is found that
<span>This type of expansion can occur either in a hot or cold universe, under the right ... but not ordinary atomic matter made from electrically neutral atoms.</span>
