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3 years ago

What is the cation and anion of NaOH

Chemistry

2 answers:

mezya [45]3 years ago

7 0

Answer: Na (sodium ) is the cation, OH is the anion.

Explanation: Na (sodium) has an oxidation number of +1 since it is in group 1 alkali metals. Most metals are cations. For OH- (hydroxide) it has a negative 1 charge so it is the anion in the compound NaOH ( sodium hydroxide.

Wewaii [24]3 years ago

6 0

Answer:

naoh is called sodium hydroxide,

Explanation:

hope this helps

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What is the Ionic Equation and Net Ionic Equation for BaCl2 + Al2(SO4)=> 3Ba(SO4) + 2AlCl3?

Nikitich [7]

I think you want to ask the complete ionic equation and net ionic equation. For complete ionic equation: 3Ba2+ + 6Cl- + 2Al3+ + 3SO42- -->3BaSO4 + 2Al3+ + 6Cl-. For net ionic equation: 3Ba2+ + 3SO42- -->3BaSO4.

8 0

3 years ago

What is the mass of 4.50 moles of magnesium chloride, MgCl2?

Vedmedyk [2.9K]

Answer:

427.5g

Explanation:

Given parameters:

Number of moles = 4.5moles

Unknown:

Mass of MgCl₂ = ?

Solution:

To solve this problem;

Mass = number of moles x molar mass

Molar mass of MgCl₂ = 24 + 2(35.5) = 95g/mol

Mass = 4.5 x 95 = 427.5g

7 0

3 years ago

How many molecules are in 3.8 mols of copper?

ioda

Answer:

Hi there!

The correct answer is 2.29 x $10^{24}$ molecules

Explanation:

To convert from the moles to molecules:

1 mole = 6.022 x 10²³ molecules

so basically you multiply 3.8 by 6.022 x 10²³

and you get: 2.29 x $10^{24}$

5 0

4 years ago

Does the density of an object depend on its size? Explain?.

evablogger [386]

No, the density of an object does not depend on its size.

A piece of glass with a volume of 10 cm³ may have a mass of 27 g. Its density is

D = m/V = 27 g/10 cm³ = 2.7 g/cm³

A piece of the same type of glass with a volume of 20 cm³ will have a mass

of 54 g. Its density is

D = m/V = 54 g/20 cm³ = 2.7 g/cm³

Thus, density does not change with the size of an object. Density is an intensive property.

3 0

3 years ago

Consider the reaction: CO2(g) + CCl4(g) ⇌ 2 COCl2(g) ΔG° = 46.9 kJ Under the following conditions at 25 oC: LaTeX: P_{CO_2}P C O

Mamont248 [21]

Answer : The value of $\Delta G_{rxn}$ is, $-47.0kJ/mole$

Explanation :

The formula used for $\Delta G_{rxn}$ is:

$\Delta G_{rxn}=\Delta G^o+RT\ln K_p$ ............(1)

where,

$\Delta G_{rxn}$ = Gibbs free energy for the reaction

$\Delta G_^o$ = standard Gibbs free energy = 46.9 kJ

R = gas constant = 8.314 J/mole.K

T = temperature = $25^oC=273+25=298K$

$K_p$ = equilibrium constant

First we have to calculate the value of $K_p$ .

The given balanced chemical reaction is,

$CO_2(g)+CCl_4(g)\rightarrow 2COCl_2(g)$

The expression for reaction quotient will be :

$K_p=\frac{(p_{COCl_2})^2}{(p_{CO_2})\times (p_{CCl_4})}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$K_p=\frac{(0.653)^2}{(0.459)\times (0.984)}$

$K_p=0.944$

Now we have to calculate the value of $\Delta G_{rxn}$ by using relation (1).

$\Delta G_{rxn}=\Delta G^o+RT\ln K_p$

Now put all the given values in this formula, we get:

$\Delta G_{rxn}=-46.9kJ/mol+(8.314\times 10^{-3}kJ/mole.K)\times (298K)\ln (0.944)$

$\Delta G_{rxn}=-47.0kJ/mol$

Therefore, the value of $\Delta G_{rxn}$ is, $-47.0kJ/mole$

3 0

3 years ago