There are 0.19 ((1.3*3.46)/(0.082*274.27) moles of gas are in the container. This problem can be solved using the ideal gas law formula which stated as PV=nRT where P is the gas' pressure, v is the gas' volume, n is the gas' mole amount, R is the constant gas standard (0.082), and T is the gas' temperature<span>.</span>
Answer:
The added energy in the hot water causes water molecules to move faster and sucrose molecules to vibrate faster.
Explanation:
This added movement tends to make the bonds between sucrose molecules easier to overcome.
Hope it helps :-)
Answer:
pressure altitude and radiation
Explanation:
beacuse in atmosphere there is aire pressure atmospheric pressure and ofcourse radiation is there as well as altitude at heights
Answer:
[H₂] = 1.61x10⁻³ M
Explanation:
2H₂S(g) ⇋ 2H₂(g) + S₂(g)
Kc = 9.30x10⁻⁸ = ![\frac{[H_{2}]^2[S_{2}]}{[H_{2}S]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH_%7B2%7D%5D%5E2%5BS_%7B2%7D%5D%7D%7B%5BH_%7B2%7DS%5D%5E2%7D)
First we <u>calculate the initial concentration</u>:
0.45 molH₂S / 3.0L = 0.15 M
The concentrations at equilibrium would be:
[H₂S] = 0.15 - 2x
[H₂] = 2x
[S₂] = x
We <u>put the data in the Kc expression and solve for x</u>:
We make a simplification because x<<< 0.0225:
x = 8.058x10⁻⁴
[H₂] = 2*x = 1.61x10⁻³ M
Answer:
10kg = 10 x 1000 = 10,000g
Explanation:
To know the quantity with the largest mass, we have to express all the units in grams:
for: 2 x 10mg = 2 x 10 x 10⁻³ = 0.02g
0.001kg = 0.001 x 1000 = 1g
1 x 10⁵ng = 1 x 10⁵ x 10⁻⁹ = 0.0001g
2 x 10²cg = 2 x 10² x 10⁻² = 2g
10kg = 10 x 1000 = 10,000g
Note:
10⁻ ¹ deci(d)
10⁻² centi(c)
10⁻³ milli(m)
10⁻⁹ nano(n)
10³ kilo(k)
