The concentration of hydroxide ion is 5 
10^
−
14 M.
<u>Explanation:</u>
Consider the equilibrium of this acid's dissociation,
H
C
l
O
4 ⇌ H
+ + C
l
O 4
-
Moreover, let's assume that H
C
l
O
4 is a strong acid and will fully dissociate.
Hence,
[
H
+
] = 0.20 M
Now, recall,
K
w = [
H
+
]
[
O
H
−
] = 1.0 10
^−
14
Hence,
⇒
[
O
H
−
] = K
w / [
H
+
] = 5 10^
−
14 M.
Answer:
c. reversible favoring products, equilibrium constants are calculated in an equation of the type aA + bB = cC + dD, were Keq = ([C][D]) / ([A][B]).
Explanation:
If the equilibrium constant is just greater than 1, that means that the products are favored.
Answer:
The correct option is: B. 33%
Explanation:
Orbital hybridisation refers to the mixing of atomic orbitals of the atoms in order to form new hybrid orbitals. The concept of orbital hybridization is used to explain the structure of a molecule.
The sp² hybrid orbitals are formed by the hybridization of one 2s orbital and two 2p orbitals. <u>The three sp² hybrid orbitals formed have 33% s character and 67% p character.</u>
Answer:
The correct answer is - alpha particle and positron.
Explanation:
In this question, it is given that, 38^88Sr decays to 34^84Kr, which means there is an atomic number decrease by 4, 38 to 34, and atomic mass decreases by 4 as well 88 to 84.
A decrease in the atomic mass is possible only when there is an emission of the alpha particle as an alpha particle is made of 2 protons and 2 neutrons. If an atom emits an alpha particle, there is a change in atomic number as it decreases by two, and its mass number decreases by four.
So after the emission of an alpha particle, the new atom would be
38^88Sr=> 36^84X => 34^84Kr
so there is also two positron emission that leads to decrease in atomic number by one with each emission:
38^88Sr=> 2^4He+ 36^84X => 36^84X + 2(1^0β+) => 34^84Kr
Positron decay is the conversion of a proton into a neutron with the emission of a positron that causes the atomic number is decreased by one, which causes a change in the elemental identity of the daughter isotope.
True.
This is a combination of an anion and a cation to form a neutral compound.
