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3 years ago

What is the ground state electron configuration for magnesium?

Chemistry

1 answer:

Stella [2.4K]3 years ago

5 0

Magnesium :

<span>[Ne] 3s²</span>

Answer A

hope this helps!

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Data has been collected to show that at a given wavelength in a 1 cm pathlength cell, Beer's Law for the absorbance of Co2 is li

White raven [17]

Answer : The concentration of a solution with an absorbance of 0.420 is, 0.162 M

Explanation :

Using Beer-Lambert's law :

$A=\epsilon \times C\times l$

As per question, at constant path-length there is a direct relation between absorbance and concentration.

$\frac{A_1}{A_2}=\frac{C_1}{C_2}$

where,

A = absorbance of solution

C = concentration of solution

l = path length

$A_1$ = initial absorbance = 0.350

$A_2$ = final absorbance = 0.420

$C_1$ = initial concentration = 0.135 M

$C_2$ = final concentration = ?

Now put all the given value in the above relation, we get:

$\frac{0.350}{0.420}=\frac{0.135}{C_2}$

$C_2=0.162M$

Thus, the concentration of a solution with an absorbance of 0.420 is, 0.162 M

4 0

3 years ago

3. What characteristics of lumpfish make them unique? (Select all that apply.)

stiks02 [169]

Answer:

the male carries the babies

the male guards the nest

The male oxygenates the embryos

Explanation: males of lump fish dont do good as pets but u can train them brrrrrrr

5 0

3 years ago

Read 2 more answers

Consider the following reaction at a high temperature. Br2(g) ⇆ 2Br(g) When 1.35 moles of Br2 are put in a 0.780−L flask, 3.60 p

UNO [17]

Answer : The equilibrium constant $K_c$ for the reaction is, 0.1133

Explanation :

First we have to calculate the concentration of $Br_2$ .

$\text{Concentration of }Br_2=\frac{\text{Moles of }Br_2}{\text{Volume of solution}}$

$\text{Concentration of }Br_2=\frac{1.35moles}{0.780L}=1.731M$

Now we have to calculate the dissociated concentration of $Br_2$ .

The balanced equilibrium reaction is,

$Br_2(g)\rightleftharpoons 2Br(aq)$

Initial conc. 1.731 M 0

At eqm. conc. (1.731-x) (2x) M

As we are given,

The percent of dissociation of $Br_2$ = $\alpha$ = 1.2 %

So, the dissociate concentration of $Br_2$ = $C\alpha=1.731M\times \frac{1.2}{100}=0.2077M$

The value of x = 0.2077 M

Now we have to calculate the concentration of $Br_2\text{ and }Br$ at equilibrium.

Concentration of $Br_2$ = 1.731 - x = 1.731 - 0.2077 = 1.5233 M

Concentration of $Br$ = 2x = 2 × 0.2077 = 0.4154 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be :

$K_c=\frac{[Br]^2}{[Br_2]}$

Now put all the values in this expression, we get :

$K_c=\frac{(0.4154)^2}{1.5233}=0.1133$

Therefore, the equilibrium constant $K_c$ for the reaction is, 0.1133

7 0

3 years ago

Consultați sistemul periodic și aranjați în ordinea creșterii caracterului nemetalic următoarele elemente:

lukranit [14]

I’m sorry I just really need points rn I love you

7 0

3 years ago

Hello Friends Can Yall Plz Help Me For Brainliest Don’t Comments No B.S Yu Will Get Cursed out show ya work

VARVARA [1.3K]

Answer:

it is b

Explanation:

mid ocean ridge diverges meaning it moving in two different direction horizontally - left to right

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3 years ago