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2 years ago

The solubility product of AgCl is 1.4 x 10-4 at 100°C. Calculate the solubility of AgCl in

Chemistry

1 answer:

marshall27 [118]2 years ago

5 0

Answer:

AgCl=Ag+ + Cl-

1.4×10^-4 =x × x

x²=1.4×10^-4

x=√(1.4×10^-4)

x=0.012

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An atom X has 2 electrons in its outer orbit. What will it do to form a stable ion?

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2 years ago

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The element in Group 14 Period 4 has how many neutrons and is it a metal, nonmetal, metalloid or noble gas.

monitta

Number of neutrons=41, and it is metalloid

<h3>Further explanation</h3>

Group 14⇒valence electron = 4(ns²np²)

Period 4⇒n=4

So electron configuration of the element :

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p² = 32 electron=atomic number

The element with atomic number 32, which is in period 4 and group 14 is Ge-Germanium

There are seven elements that can be classified as metalloids, namely boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te), and polonium (Po).

While the mass number: 73

So the number of neutrons = mass number-atomic number

$\tt 73-32=41$

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