Since angle A = Angle B, I believe you would write it out like this:
6x+12=3x+63
subtract 3x from both sides, then subtract 12 from both sides.
3x=51
divide 51 by 3 to find x.
x=17
Now to find the measure of angle A.
A = 6(17)+12
A = 102+12
A = 114, angle A is 114 degrees.
Answer:
85.6 cm^2
Step-by-step explanation:
The area of the central triangle bounded by each of the sides can be computed as ...
A = (1/2)r²sin(α) . . . . where α is the central angle, 360°/5 = 72°
There are 5 such triangles, so the area of the pentagon is ...
A = (5/2)(6 cm)²sin(72°) ≈ 85.595 cm²
The area of the regular pentagon of radius 6 cm is about 85.6 cm².
Answer:
4
Step-by-step explanation:
its 4 lol