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Anastaziya [24]
3 years ago
12

Factor the following expression.

Mathematics
2 answers:
Marysya12 [62]3 years ago
4 0

10x^5 + 5x^3 - 14x^2 - 7

= 5x^3(2x^2 + 1) - 7(2x^2 + 1)

= (5x^3 - 7)(2x^2 + 1)

Answer is D

(5x^3 - 7)(2x^2 + 1)

Dimas [21]3 years ago
4 0

Answer:

D.

Step-by-step explanation:

Let's use common factor gruping terms. We have that we have a common factor between the two left terms and another common factor between the two right terms. Then,

for the two left terms we take the common divisor, in this case 5 and the x with the minimun exponent, that is 5x^3.

for the two right terms we take the common divisor, in this case -7 and the x with the minimun exponent, in this case the -7 has no x so we don't include it in the common factor.

10x^5 + 5x^3 - 14x^2 - 7 = 5x^3(2x^2+1)-7(2x^2+1)

Now, we use common factor again, this time the common factor will be 2x^2+1:

10x^5 + 5x^3 - 14x^2 - 7 = 5x^3(2x^2+1)-7(2x^2+1)= (2x^2+1)(5x^3-7).

Then, the answer is D.

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Read 2 more answers
EF is the median of trapezoid ABCD.
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Answer:

Part A) x = 11

B) length of BC =  x + 12 =  x + 12 = 11 + 12 =23

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length of AD =  3x - 18 =  3(11) - 4 = 33 - 4 =29

Step-by-step explanation:

Median of trapezium is m=\frac{base1+base2}{2}

In provided figure, base1 is x+12 and base2 is 3x-4

A) solve for value of x

calculate the median m=\frac{base1+base2}{2}

4x-18=\frac{x+12+3x-4}{2}

4x-18=\frac{4x+8}{2}

4x-18=2x+4

2x-18=4

2x = 18 + 4

2x = 22

x = 11

B) To find the length of BC, AD and EF , put the value of x in equation of lines

length of BC =  x + 12 =  x + 12 = 11 + 12 =23

length of EF =  4x - 18 =  4(11) - 18 = 44 - 18 =26

length of AD =  3x - 4 =  3(11) - 4 = 33 - 4 =29

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3 years ago
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