Answer : The mass of nitrogen dioxide is, 17.6 grams
The formula of limiting reagent is, 
The mass of excess reagent remains is, 3.74 grams
Explanation : Given,
Mass of
= 11.5 g
Mass of
= 9.91 g
Molar mass of
= 30 g/mol
Molar mass of
= 32 g/mol
First we have to calculate the moles of
and
.


and,


Now we have to calculate the limiting and excess reagent.
The balanced chemical equation is:

From the balanced reaction we conclude that
As, 2 mole of
react with 1 mole of 
So, 0.383 moles of
react with
moles of 
From this we conclude that,
is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Moles of excess reagent remains = 0.309 - 0.192 = 0.117 mol
Now we have to calculate the mass of excess reagent remains.

Molar mass of
= 32 g/mole

Now we have to calculate the moles of 
From the reaction, we conclude that
As, 2 mole of
react to give 2 mole of 
So, 0.383 mole of
react to give 0.383 mole of 
Now we have to calculate the mass of 

Molar mass of
= 46 g/mole
