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riadik2000 [5.3K]
3 years ago
14

What do i do if my crush likes another girl?

Chemistry
2 answers:
UkoKoshka [18]3 years ago
7 0

Answer:

personaly i wouldn't get involved but you wanna tell him/her how you fell go for it.

Mamont248 [21]3 years ago
5 0

Answer: tell that person how u feel

Explanation: If it doesn’t go well ask if u can just stay friends

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A sealed container holding 0.0255 L of an ideal gas at 0.991 atm and 69 ∘ C is placed into a refrigerator and cooled to 43 ∘ C w
ANEK [815]

Answer:

The final pressure of the gas is 0.915atm

Explanation:

We have to apply the Charles Gay Lussac Law, where the pressure changes directly proportional to absolute T°

- No change in volume

- The same moles in both situations

P1 / T1  =  P2 / T2

0.991 atm / 342K = P2 / 316k

(0.991 atm / 342K) . 316K = P2

0.915 atm = P2

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3 years ago
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What should be included in a science conclusion
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A science conclusion should simply have a statement identifying whether your experiment’s aim turned out to be true or false
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Calculate the net force<br> 175 N<br> 1125 N
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When calcium carbonate reacts with hydrochloric acid, calcium ions are transferred to the solution. Write only one net ionic equ
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2 years ago
The combustion of 0.570 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera
torisob [31]

Answer:

The temperature change from the combustion of the glucose is 6.097°C.

Explanation:

Benzoic acid;

Enthaply of combustion of benzoic acid = 3,228 kJ/mol

Mass of benzoic acid = 0.570 g

Moles of benzoic acid = \frac{0.570 g}{122.12 g/mol}=0.004667 mol

Energy released by 0.004667 moles of benzoic acid on combustion:

Q=3,228 kJ/mol \times 0.004667 mol=15.0668 kJ=15,066.8 J

Heat capacity of the calorimeter = C

Change in temperature of the calorimeter = ΔT = 2.053°C

Q=C\times \Delta T

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Glucose:

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=2.900 g

Moles of glucose = \frac{2.900 g}{180.16 g/mol}=0.016097 mol

Energy released by the 0.016097 moles of calorimeter  combustion:

Q'=2,780 kJ/mol \times 0.016097 mol=44.7491 kJ=44,749.1 J

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

Q'=C\times \Delta T'

44,749.1 J=7,338.92 J/^oC\times \Delta T'

\Delta T'=6.097^oC

The temperature change from the combustion of the glucose is 6.097°C.

6 0
2 years ago
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