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4 years ago

Is vinegar a compound or a mixture?

Chemistry

1 answer:

Nady [450]4 years ago

7 0

Vinegar is a mixture because other thing are added to make a whole new thing

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(01.01 MC)

marysya [2.9K]

I think the answer is D (number 4)

4 0

3 years ago

** worth 20 points + brainliest **

Bad White [126]

Answer : The correct option is, (D) $83^oC$

Solution :

Formula used :

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

where,

Q = heat released = -1300 J

m = mass of water = 40 g

c = specific heat of water = $4.18J/g^oC$

$\Delta T=\text{Change in temperature}$

$T_{final}$ = final temperature = ?

$T_{initial}$ = initial temperature = $91.0^oC$

Now put all the given values in the above formula, we get the final temperature of water.

$-1300J=40g\times 4.18J/g^oC\times (T_{final}-91.0^oC)$

$T_{final}=83.2^oC\approx 83^oC$

Therefore, the final temperature of the water is, $83^oC$

5 0

3 years ago

A voltaic cell is constructed in which the anode is a Fe|Fe2 half cell and the cathode is a Cd|Cd2 half cell. The half-cell comp

Svetradugi [14.3K]

Answer: The Anode reaction is $Fe(s)\rightarrow Fe^{2+}(aq)+2e^-$

Explanation:

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

Oxidation reaction is defined as the reaction in which a substance looses its electrons.Oxidation occurs at anode.

Anode : $Fe(s)\rightarrow Fe^{2+}(aq)+2e^-$

Reduction reaction is defined as the reaction in which a substance gains electrons. Reduction occurs at cathode.

Cathode : $Cd^{2+}(aq)+2e^-\rightarrow Cd(s)$

3 0

3 years ago

Determine the empirical formula of a compound containing 40. 6 grams of carbon, 5. 1 grams of hydrogen, and 54. 2 grams of oxyge

zavuch27 [327]

The empirical formula is C₂H₃O₂

<h3>What is Empirical formula of a compound ?</h3>

The empirical formula is the simplest whole number ratio of elements present in a compound.

The total molar mass of the compound is 118.084 g/mol.

mass of Carbon present = 40.6

mass of Hydrogen present = 5.1 grams

mass of Oxygen present = 2 grams

Moles of C = 40.6/12 = 3.38

Moles of H = 5.1/1.008 = 5

Moles of Oxygen = 54.2/15.999 = 3.38

Ratio of Moles of C to Oxygen is 1 : 1

Ratio of Moles of C to H is 1/1.5

Multiplying each mole fraction by 2

The empirical formula is C₂H₃O₂

To know more about Empirical Formula

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5 0

2 years ago

If an unknown substance CANNOT be broken down into simpler substances, it is

Fynjy0 [20]

If an unknown substance CANNOT be broken down into simpler substances, it is AN ELEMENT made of one kind of atom.

7 0

3 years ago

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