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Papessa [141]
3 years ago
14

Where would electrons in the d sub level be found

Chemistry
1 answer:
notka56 [123]3 years ago
8 0

Answer:

d sub level starts from the 3rd energy level; means you can see electrons in d sub level in any energy levels after third one.

So the answer is "In any energy levels ≥ 3"

A simple information ; s sub level is in any energy level,

p sub level is in any energy level beginning from the 2nd energy level,

d sub level appears ≥ 3rd energy level

f sub level appears in 4th energy level and over.

Hope it helps!

#MissionExam001

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Which statement does NOT apply to Alkenes?
nikdorinn [45]

Answer:

They are more stable than alkanes

Explanation:

  • <em><u>Alkenes</u></em><em><u> are a type of unsaturated hydrocarbons </u></em>which means they have a<u> double bond</u> in their structure, or lack maximum number of hydrogen atoms on each carbon.
  • Alkenes have a general formula of CnH2n. They are called <u>unsaturated hydrocarbons</u> since they have a double bond. They are therefore less stable compared to alkanes and also are readily reactive.
6 0
3 years ago
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when using a clamp and ring stand to hold glassware and tools, what is the best position for the clamp?
lora16 [44]
The bottom







Explanation:
4 0
3 years ago
To completely convert 9. 0 moles of hydrogen gas (h2) to ammonia gas, how many moles of nitrogen gas (n2) are required?
evablogger [386]

To completely convert 9. 0 moles of hydrogen gas (h2) to ammonia gas, 3.0 moles of nitrogen gas (n2) are required.

<h3>What are moles?</h3>

The mole is a SI unit of measurement that is used to calculate the quantity of any substance.

<h3 />

The given reaction is \rm  N_2(g) + 3H_2(g) \rightarrow 2NH_3(g)

By the stoichiometry rule of ratio hydrogen: nitrogen

3 : 1

The reacted moles of nitrogen is equals to H/3 moles of reacted hydrogen

So, moles of nitrogen  

\rm Moles\; of\; nitrogen = \dfrac{9.0 }{3} =3.0\;mol

Thus, 3.0 moles of nitrogen gas (n2) are required.

Learn more about moles

brainly.com/question/26416088

#SPJ4

3 0
2 years ago
A sample of xenon gas occupies a volume of 6.80 L at 52.0°C and 1.05 atm. If it is desired to increase the volume of the gas sam
Pavlova-9 [17]

Answer:

207.03°C

Explanation:

The following data were obtained from the question:

V1 (initial volume) = 6.80 L

T1 (initial temperature) = 52.0°C = 52 + 273 = 325K

P1 (initial pressure) = 1.05 atm

V2 (final volume) = 7.87 L

P2 (final pressure) = 1.34 atm

T2(final temperature) =?

Using the general gas equation P1V1/T1 = P2V2/T2, the final temperature of the gas sample can be obtained as follow:

P1V1/T1 = P2V2/T2

1.05 x 6.8/325 = 1.34 x 7.87/T2

Cross multiply to express in linear form as shown below:

1.05 x 6.8 x T2 = 325 x 1.34 x 7.87

Divide both side by 1.05 x 6.8

T2 = (325 x 1.34 x 7.87) /(1.05 x 6.8)

T2 = 480.03K

Now, let us convert 480.03K to a number in celsius scale. This is illustrated below:

°C = K - 273

°C = 480.03 - 273

°C = 207.03°C

Therefore, the final temperature of the gas will be 207.03°C

5 0
3 years ago
El compuesto es soluble en agua y conduce la eletricidad
salantis [7]

Answer:

creo que si

Explanation:

por que si vienes a ver has un experimento con agua y electricidad. por eso es que el compuesto es soluble en agua y conduce la electricidad

6 0
3 years ago
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