A lithium atom starts from rest at a position x = xo and falls toward zinc atom with an acceleration that depends on their separ
ation as a(x) = 4Eϵ/m { 12 (σ^12/σ^13) -6 (σ^6/σ^7) where ϵ, m, and σ are positive constants, and the zinc atom stays fixed at position x = 0, Assume that xo > 2^(1/6)σ. a. Find an expression for how the velocity of the moving lithium atom depends on x. (It will also depend on ϵ, m, xo and σ) b. What is the distance of closest approach of the the two atoms (in terms of σ and xo)?
1 answer:
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Answer: The concentration of ions in the resulting solution is 1.16 M.
Explanation:
To calculate the molarity of the solution after mixing 2 solutions, we use the equation:
where,
are the n-factor, molarity and volume of the
are the n-factor, molarity and volume of the
We are given:
Putting all the values in above equation, we get
The concentration of ions in the resulting solution will be same as the molarity of solution which is 1.16 M.
Hence, the concentration of ions in the resulting solution is 1.16 M.
Answer:
1.62
Explanation:
From the given information:
number of moles of benzamide
= 0.58 mole
The molality =
= 0.6837
Using the formula:
where;
dT = freezing point = 27
l = Van't Hoff factor = 1
kf = freezing constant of the solvent
∴
2.7 °C = 1 × kf × 0.6837 m
kf = 2.7 °C/ 0.6837m
kf = 3.949 °C/m
number of moles of NH4Cl =
= 1.316 mol
The molality =
= 1.5484
Thus;
the above kf value is used in determining the Van't Hoff factor for NH4Cl
i.e.
9.9 = l × 3.949 × 1.5484 m
l = 1.62