A lithium atom starts from rest at a position x = xo and falls toward zinc atom with an acceleration that depends on their separ
ation as a(x) = 4Eϵ/m { 12 (σ^12/σ^13) -6 (σ^6/σ^7) where ϵ, m, and σ are positive constants, and the zinc atom stays fixed at position x = 0, Assume that xo > 2^(1/6)σ. a. Find an expression for how the velocity of the moving lithium atom depends on x. (It will also depend on ϵ, m, xo and σ) b. What is the distance of closest approach of the the two atoms (in terms of σ and xo)?
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Hello!
To solve this problem, we will use the Boyle's Law, which describes how pressure changes when volume changes and vice-versa. The equation for this law is the following one, and we'll clear for V2:
So, the final volume after increasing the pressure would be 2,7 L. That means that volume decreases when the pressure increases
Have a nice day!
To solve this problem, we will use the Boyle's Law, which describes how pressure changes when volume changes and vice-versa. The equation for this law is the following one, and we'll clear for V2:
So, the final volume after increasing the pressure would be 2,7 L. That means that volume decreases when the pressure increases
Have a nice day!