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Ulleksa [173]
3 years ago
9

A lithium atom starts from rest at a position x = xo and falls toward zinc atom with an acceleration that depends on their separ

ation as a(x) = 4Eϵ/m { 12 (σ^12/σ^13) -6 (σ^6/σ^7) where ϵ, m, and σ are positive constants, and the zinc atom stays fixed at position x = 0, Assume that xo > 2^(1/6)σ. a. Find an expression for how the velocity of the moving lithium atom depends on x. (It will also depend on ϵ, m, xo and σ) b. What is the distance of closest approach of the the two atoms (in terms of σ and xo)?

Chemistry
1 answer:
rusak2 [61]3 years ago
3 0

Answer:

Please refer to the attachment for answers.

Explanation:

Please refer to the attachment for explanation

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