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Snezhnost [94]
3 years ago
7

If 5.2 moles of oxygen react, how many moles of nitrogen monoxide are produced? _______ Round to the nearest tenth, include unit

s on your answer.
Chemistry
2 answers:
MArishka [77]3 years ago
7 0

Answer:

10.4 moles

Explanation:

Given parameters:

Number of moles of oxygen = 5.2moles

Number of moles of nitrogen monoxide = ?

Solution:

To solve this problem, we need to work from the known to the unknown specie according to the reaction.

Oxygen gas is known and we can estimate the amount of mole of nitrogen monoxide;

         

Let us write the balanced reaction equation;

                N₂    +      O₂          →          2NO

  according to this reaction;

       1 mole of oxygen gas will produce 2 mole of NO

       5.2 moles of oxygen gas will produce  (5.2 x 2)moles  = 10.4moles

Lyrx [107]3 years ago
3 0

Answer:

10.4 moles

Explanation:

The equation of the reaction between oxygen and nitrogen to produce nitrogen monoxide is,

N₂(g) + O₂ (g)→ 2NO (g)

1        :   1         :   2

This mean 1 mole of nitrogen gas react with 1 mole of oxygen gas to give 2 moles of nitrogen monoxide

In this case the if 5.2 moles of Oxygen react, it will give 2 moles of NO

5.2*2=10.4

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Answer:

Higher than 59 °C because dipole-dipole interactions in iodine monochloride are stronger than dispersion forces in bromine.

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6 0
4 years ago
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alina1380 [7]

Mass of H₂ needed to react with O₂ : 1.092 g

<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

Reaction

O₂(g) + 2H₂(g) → 2H₂O(g)

mass of O₂ : 8.75 g

mol O₂(MW=32 g/mol) :

\tt \dfrac{8.75}{32}=0.273

From the equation, mol ratio of O₂ : H₂ = 1 : 2, so mol H₂ :

\tt \dfrac{2}{1}\times 0.273=0.546

Mass H₂ (MW=2 g/mol) :

\tt 0.546\times 2=1.092~g

4 0
3 years ago
Read 2 more answers
Complete combustion of 5.90 g of a hydrocarbon produced 18.8 g of CO2 and 6.75 g of H2O.
Inessa05 [86]
First we have to find moles of C:
Molar mass of CO2:
12*1+16*2 = 44g/mol
(18.8 g CO2) / (44.00964 g CO2/mol) x (1 mol C/ 1 mol CO2) =0.427 mol C 
Molar mass of H2O:
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As there is 2 moles of H in H2O,
So,

<span>(6.75 g H2O) / (18.01532 g H2O/mol) x (2 mol H / 1 mol H2O) = 0.74mol H </span>

<span>Divide both number of moles by the smaller number of moles: </span>
<span>As Smaaler no moles is 0.427:
So,
Dividing both number os moles by 0.427 :
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<span>(0.74 mol H) / 0.427 = 1.733 </span>

<span>To achieve integer coefficients, multiply by 2, then round to the nearest whole numbers to find the empirical formula: 
C = 1 * 2 = 2
H = 1.733 * 2 =3.466
So , the empirical formula is C2H3</span>
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3 years ago
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4 years ago
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Answer:

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6 0
3 years ago
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