Answer:
4
Step-by-step explanation:
3/4÷3/16
3/4×16/3
3•16=48
4×3=12
48÷12=4
The smallest perimeter is 72.44 inches. The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is unknown. As much as possible, the sum of the length of the two remaining side must be greater than the other side. Given the side is 30, then the sum of the two remaining sides should be greater than 30 inches.
<span>437 = (21 + x)(21 - x), then x = 2, -2</span>
Answer:
15<x<27
Step-by-step explanation:
Rule for the sides of a triangle:
The sum of the two smallest sides of a triangle must be greater than the biggest side.
In this question:
Sides of 6, 21 and x. We have to find the range for x.
If 21 is the largest side:
Two smallest are 6 and x.
x + 6 > 21
x > 21 - 6
x > 15
If x is the largest side:
Two smallest and 6 and 21. So
21 + 6 > x
27 > x
x < 27
Then
x has to be greater than 15 and smaller than 27. So the answer is:
15<x<27
Answer:
join the y-related together and the others together
ie -7+1/3y
thats the shortest form one can drill down to, so that should be the answer
Step-by-step explanation:
