Question

Three force vectors are added together. One has a magnitude of 9 N, the second one a magnitude of 18 N, and the third a magnitude of 15 N. What can we conclude about the magnitude of the net force vector? Explain. I. It must equal 42 N. II. It cannot be 0 N. III. Anything from –42 N to +42 N. IV. It can be anything from 0 N to 42 N. V. None of the above can be concluded.

Answer 1

Answer:

true I, II and III

Explanation:

The force is a vector quantity, by local it must be added as vectors, we can suppose several cases

.i) the vectors are colonial, so their sum is maximum

       F_max = 9 + 15 + 18

       F_max = 42 N

This is the maximum value

ii) the anti-parallel vectors giving a minimum value

     F_min = 15 + 9-18

     F_min = 6 N

iii) the vectors have angles between them, so we must use the Pythagorean theorem to find the resultant, which is an intermediate value between the two extreme values ​​found.

Let's take a look at each statement

I) True This is the maximum value of the force if all the vectors are colonial

II) True The minimum value is 6 N, so zero can never be reached

III) True these bores are between the maximum values ​​and the direction of the vectors, lower values ​​occur when the forces have angular between them

IV) False. Force can never reach zero

V) False. Several of the above are conclusions of the exercise