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Art [367]
3 years ago
9

What is voltage and current?

Physics
2 answers:
MrMuchimi3 years ago
4 0

Voltage - An electromotive force or potential difference expressed in volts.

Current - A flow of electricity which results from the ordered directional movement of electrically charged particles.

vladimir1956 [14]3 years ago
4 0
Current is a rate at which electric charge flows past a point in a circuit. Voltage is the potential difference in charge between two points in an electrical field.
You might be interested in
Please solve this question ​
lesantik [10]

Answer:

88200 Pa

it is because

height =9m

density=1000kg/m(cube)

gravity = 9.8m/s(square)

now,

P=d×g×h

= 1000×9.8×9

=88200pa

8 0
3 years ago
A ball of mass 2 kg is kept on the hill of height 3 km. Calculate the potential energy possessed by it ?
zysi [14]
We know that -

P.E=m*g*h

Where,

m = mass

g = acceleration due to gravity

h=height

First we convert height into meters.

1 km = 1000 meters

3 km = 1000 * 3 meters = 3000 meters

So, putting the values in the above formula, and by taking 'g' = 9.8 m/s², we get-

P.E.= 2*3000*9.8

P.E.= 58800 Joules

P.E.= 58.8 kJ

7 0
4 years ago
Read 2 more answers
What comes down but never goes up
White raven [17]

Answer:

Explanation:

rain and your age

5 0
3 years ago
A spherical balloon is made from a material whose mass is 3.30 kg. The thickness of the material is negligible compared to the 1
stellarik [79]

Answer:

563712.04903 Pa

Explanation:

m = Mass of material = 3.3 kg

r = Radius of sphere = 1.25 m

v = Volume of balloon = \frac{4}{3}\pi r^3

M = Molar mass of helium = 4.0026\times 10^{-3}\ kg/mol

\rho = Density of surrounding air = 1.19\ kg/m^3

R = Gas constant = 8.314 J/mol K

T = Temperature = 345 K

Weight of balloon + Weight of helium = Weight of air displaced

mg+m_{He}g=\rho vg\\\Rightarrow m_{He}=\rho vg-m\\\Rightarrow m_{He}=1.19\times \frac{4}{3}\pi 1.25^3-3.3\\\Rightarrow m_{He}=6.4356\ kg

Mass of helium is 6.4356 kg

Moles of helium

n=\frac{m}{M}\\\Rightarrow n=\frac{6.4356}{4.0026\times 10^{-3}}\\\Rightarrow n=1607.85489

Ideal gas law

P=\frac{nRT}{v}\\\Rightarrow P=\frac{1607.85489\times 8.314\times 345}{\frac{4}{3}\pi 1.25^3}\\\Rightarrow P=563712.04903\ Pa

The absolute pressure of the Helium gas is 563712.04903 Pa

3 0
3 years ago
Two hockey pucks, labeled A and B, are initially at rest on a smooth ice surface and are separated by a distance of 18.0 m. Simu
salantis [7]

Answer: pick A moves 10.2 metre

Explanation: since they were given a quick push simultaneously the product of their distance moved and velocity would be equal.

Let the distance moved by puck B x then that of puck A would be 18-x.

So therefore we have that,

1.3*(18-x) = 1.7*x

23.4 - 1.3x = 1.7x

23.4=3x

Making x subject of formula we have

x = 23.4/3 = 7.8m

But the distance moved by puck A is 18-x. So therefore,

18-7.8=10.2meter

6 0
3 years ago
Read 2 more answers
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