I. Positive acceleration increases velocity. Negative acceleration decreases velocity. runner A sped up until the finish line and then slowed to a stop.
ii. Zero a acceleration implies a constant, unchanging velocity not a zero velocity. runner B achieved some velocity prior to 8s and is moving and must slow down to reach a stop.
iii. None. No aspects of this reasoning are correct. Everything she says is wrong. See iv for what/why.
iv. The sign on acceleration denotes the direction of *change in velocity* not change in direction. The sign on velocity can denote change in direction but only “forward” or “reverse” along a particular path. Cardinal direction is not indicated, generally, by the sign on velocity. It may correspond to North/South situationally but it is not an built-in feature of velocity and its sign. For example, if you are traveling with positive velocity and turn left to continue your journey you still have a positive velocity in the new direction. In fact, if you turn left again, traveling in the opposite direction as the one you started with your velocity would still be positive… in the new direction. The velocity relative to original direction could be said to be negative but that would be a confusing way to describe a journey. Maybe if you stopped the vehicle and moved in reverse, you could meaningfully say velocity was negative.
Answer:
1. E=5320.3J
2. E= 1773.45J
3. E=6.76*10^{-21}J
4. E=2.25*10^{-21}J
Explanation:
1. the thermal energy is given by the formula
where KB is the Boltzmann's constant, T is the temperature and N is the number of molecules in the system.
2. Each degree of freedom contains one half of the total energy. Hence, the energy for one degree of freedom is
3.
4.
Hope this helps!!
Answer:
Both Thomson and Rutherford used charged particles in their experiments.
Explanation:
Answer:
eazy
Explanation:
hi bro it is very hard so I can't help and I don't the answer
What are the answer options? It says which of the following. :)
