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Lynna [10]
2 years ago
8

Water waves in a small tank are 6.6 m long. They travel at a speed of 2.9 m/s. What is the frequency of the water

Physics
1 answer:
liubo4ka [24]2 years ago
8 0

Answer:

.439 Hz

Explanation:

Wavelength = 6.6 m

speed = 2.9 m/s

  2.9 = 6.6 f

f = 2.9/6.6 =  .439 Hz

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What is the current hypothesis on how the earths moon formed
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You are given a vector in the xy plane that has a magnitude of 84.0 units and a y-component of -67.0 units.
melomori [17]

Answer:

Explanation:

a)Magnitude = \sqrt{(x1-y2)^{2}  + (x1-x2)^{2} }

84=\sqrt{(0- (-67))^{2}  + (x-0)^{2} }

x= +50.67 or -50.67 units

b) We are given that the resultant is entirely in the -ve x direction which means that the y-component of the resultant is 0; It means that the y-component of the next vector = -ve of the y component of the initial vector i.e 67.

To make the magnitude 80 units in the negative x direction where the y component is 0, the x component must be -130.67(-50.67 - 80) as the x component is + 50.67units.

Magnitude = \sqrt{(0- (67))^{2}  + (-130.67)^{2} } = 146.85 units

c) The direction vector = 67/146.85 i  - 130.67/146.85 j where i corresponds to the vector in y direction and j corresponds to the vector in x direction. Or this vector is at an angle of 180 - Tan^{-1}(67/130.67)degrees i.e 152.85 degrees from the +ve x-axis.

5 0
3 years ago
Identify the person who made the correct statement.
dmitriy555 [2]
The answer is:  [C]:  Neither Juan nor Christina are correct.
_________________________________________________
Explanation:
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Consider Juan's statement:
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This statement is incorrect.  There are many instances of fossil deposits containing more than one type of organism.
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Consider Christina's statement.
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___________________________________________
As such, neither Juan nor Christina are correct. 
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Answer choices A, B, and D are ruled out.
7 0
3 years ago
A light bulb emits light uniformly in all directions. The average emitted power is 150.0 W. At a distance of 5 m from the bulb,
beks73 [17]

Answer:

a) 0.477 W/m²

b) 13.407 N/C

c) 18.96 N/C

Explanation:

P = Power = 150 W

r = Distance = 5 m

ε₀ = Permittivity of space = 8.854×10⁻¹² F/m

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\bar{S}=\frac{P}{A}\\\Rightarrow \bar{S}=\frac{150}{4\pi r^2}\\\Rightarrow \bar{S}=\frac{150}{4\pi 5^2}\\\Rightarrow \bar{S}=0.477\ W/m^2

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b) Rms value

\bar{S}=c\epsilon_0E_{rms}^2\\\Rightarrow E_{rms}=\sqrt{\frac{\bar{S}}{c\epsilon_0}}\\\Rightarrow E_{rms}=\sqrt{\frac{\bar{0.477}}{3\times 10^8\times 8.854\times 10^{-12}}}\\\Rightarrow E_{rms}=13.407\ N/C

∴ Rms value of the electric field is 13.407 N/C

c) Peak value

E_0=\sqrt 2E_{rms}\\\Rightarrow E_0=\sqrt 2\times 13.407\\\Rightarrow E_0=18.96\ N/C

∴ Peak value of the electric field is 18.96 N/C

8 0
3 years ago
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