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Pani-rosa [81]
3 years ago
14

≡↔∛ππΔ≅×π⊄∴khvjh j hjgvvvvvvvvvvvvvh jh

Chemistry
1 answer:
cupoosta [38]3 years ago
7 0

its 40

I just took the test right now to get this answer

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It might be more suitable because some data cannot use a graph to show data because there is too much data.
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What can a base substance do to a hydrogen ion?
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Answer:

Soaks them up

Explanation:

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Read 2 more answers
Chlorine has two natural isotopes, chlorine-35 and chlorine-37.
Alex Ar [27]

Answer:

The relative atomic mass of chlorine depends on the ratio between the abundance of these two naturally-occurring isotopes.

Explanation:

The relative atomic mass of an element is a weighted average of the atomic mass of its naturally-occurring isotopes. The relative abundance of each isotope gives its weight in this weighted average.

For these two naturally-occurring isotopes of chlorine:

  • The relative atomic mass of ^{35}{\rm Cl} is approximately 34.969 daltons. The relative abundance of this isotope in nature is approximately 0.758.
  • The relative atomic mass ^{37}{\rm Cl} is approximately 36.966 daltons. The relative abundance of this isotope in nature is approximately 0.242.

\begin{array}{|c|c|c|}\cline{1-3} \text{Isotope} & \text{Atomic Mass} & \text{Relative Abundance}\\ \cline{1-3} ^{35}{\rm Cl} & \approx 34.968\; \rm Da} & \approx 0.758 \\ \cline{1-3} ^{37}{\rm Cl} & \approx 36.966\; \rm Da & \approx 0.242 \\ \cline{1-3}\end{array}.

\begin{aligned}&\text{relative atomic mass of Cl} \\ &= \text{atomic mass of $^{35}{\rm Cl}$} \times \text{relative abundance of $^{35}{\rm Cl}$} \\&\quad + \text{atomic mass of $^{37}{\rm Cl}$} \times \text{relative abundance of $^{37}{\rm Cl}$} \\ &\approx 34.968\; \rm Da \times 0.758 + 36.966\; \rm Da \times 0.242 \\ &\approx 35.45\; \rm Da \end{aligned}.

The relative abundance of ^{35}{\rm Cl} is much higher than that of ^{37}{\rm Cl}. Consequently, the relative atomic mass of the element \rm Cl is closer to the atomic mass of ^{35}{\rm Cl}\! than that of ^{37}{\rm Cl}\!.

7 0
3 years ago
How many moles of Na3PO4 are in 820. grams of it?
kotegsom [21]

Answer:Hello

D is correct

Explanation:

4 0
3 years ago
What is the molality of a solution containing 3. 0 moles of nacl and 100. 0 moles of water?
Mama L [17]

The molality of a solution containing 3. 0 moles of NaCl and 100. 0 moles of water is 30 mol/kg.

The number of moles of solute in a solution equal to 1 kg or 1000 g of solvent is referred to as its molality. Mole per kilogram of solvent is the SI unit for molality.

Given:

3.0 moles of NaCl in 100 moles of water.

To find:

The molality of the solution

The moles of solute (NaCl) = 3.0 moles

The mass of solvent (water) = 100 moles (0.1 kg/mol)

Molality of a solution = Number of Moles of solute/ Mass of solvent(kg)

                                 = 3.0 moles/0.1 kg/mol

                                 = 30 mol/kg

To know more about Molality refer:

brainly.com/question/20354433

#SPJ4

                                           

4 0
2 years ago
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