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Pani-rosa [81]
3 years ago
14

≡↔∛ππΔ≅×π⊄∴khvjh j hjgvvvvvvvvvvvvvh jh

Chemistry
1 answer:
cupoosta [38]3 years ago
7 0

its 40

I just took the test right now to get this answer

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Calculate the concentration of an aqueous solution of naoh that has a ph of 11.50
Reika [66]
NaOH is a strong base and complete dissociation into Na⁺ and OH⁻ ions. 
Therefore [NaOH] = [OH⁻]
To calculate the [OH⁻], we can first find the pOH as NaOH is a basic solution.
pH + pOH = 14
Since pH = 11.50
pOH = 14 - 11.50
pOH = 2.50
We can calculate [OH⁻] by knowing pOH 
pOH = -log[OH⁻]
[OH⁻] = antilog(-pOH)
[OH⁻] = 3.2 x 10⁻³ M
therefore [NaOH] = 3.2 x 10⁻³ M
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3 years ago
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When hydrogen peroxide (H2O2) is added to potassium iodide (KI) solution, the hydrogen peroxide decomposes into water (H2O) and
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3 years ago
How many moles of mercury(II) oxide, HgO, are needed to produce 125 g of oxygen, O2? How many moles of mercury is produced?​
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Explanation:

Given that,

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