In calculating the equilibrium constant for a reaction, the coefficients of the chemical equation are used as exponents for the
1 answer:
Answer: The given statement is TRUE.
Explanation:
An equilibrium reaction is one in which rate of forward reaction is equal to the rate of backward reaction.
Equilibrium constant is defined as the ratio of the product of the concentration of products to the product of the concentration of reactants each raised to their stochiometric coefficient.
For example for the given equilibrium reaction;
Thus the given statement that in calculating the equilibrium constant for a reaction, the coefficients of the chemical equation are used as exponents for the factors in the equilibrium expression is True.
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<u>Answer:</u> The freezing point of solution is 16.5°C and the boiling point of solution is 118.2°C
<u>Explanation:</u>
To calculate the molality of solution, we use the equation:
Where,
= Given mass of solute
= 0.800 g
= Molar mass of solute
= 256.52 g/mol
= Mass of solvent (acetic acid) = 100.0 g
Putting values in above equation, we get:
- <u>Calculation for freezing point of solution:</u>
Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.
To calculate the depression in freezing point, we use the equation:
or,
where,
Freezing point of acetic acid = 16.6°C
i = Vant hoff factor = 1 (for non-electrolyte)
= molal freezing point depression constant = 3.59°C/m
m = molality of solution = 0.0312 m
Putting values in above equation, we get:
Hence, the freezing point of solution is 16.5°C
- <u>Calculation for boiling point of solution:</u>
Elevation in boiling point is defined as the difference in the boiling point of solution and freezing point of pure solution.
The equation used to calculate elevation in boiling point follows:
To calculate the elevation in boiling point, we use the equation:
or,
where,
Boiling point of acetic acid = 118.1°C
i = Vant hoff factor = 1 (for non-electrolyte)
= molal boiling point elevation constant = 3.08°C/m
m = molality of solution = 0.0312 m
Putting values in above equation, we get:
Hence, the boiling point of solution is 118.2°C
The mass of melted gold to release the energy would be 3, 688. 8 Kg
<h3>How to determine the mass</h3>The formula for quantity of energy is given thus;
Q = n × HF
Where n represents number of moles
HF represents heat of fusion
To find the number of moles, we have
235.0 = n × 12.550
number of moles = = 18. 725 moles
Note that molar mass of Gold is 197g/ mol
Let's note that;
Number of moles = mass/ molar mass
Mass = number of moles × molar mass
Mass = 18. 725 × 197
Mass = 3, 688. 8 Kg
Thus, the mass of melted gold to release the energy would be 3, 688. 8 Kg
Learn more about molar heat of fusion here:
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