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2 years ago

What is the fourth most abundant element in the universe in terms of mass?

2 answers:

8 0

The fourth most abundant element in the universe in terms of mass would be Carbon.

The first is Hydrogen, the second is Helium, and the third is oxygen.

iren [92.7K]2 years ago

4 0

The fourth most abundant element in terms of mass is Carbon.

The first, second, and third most abundant element in terms of mass are Hydrogen, Helium, and Oxygen, respectively.

Hope this helps~

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An ethylene glycol solution contains 21.4 g of ethylene glycol (C2H6O2) in 97.6 mL of water. (Assume a density of 1.00 g/mL for

8090 [49]

Answer: The freezing point and boiling point of the solution are $-6.6^0C$ and $101.8^0C$ respectively.

Explanation:

Depression in freezing point:

$T_f^0-T^f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_f$ = freezing point of solution = ?

$T^o_f$ = freezing point of water = $0^0C$

$k_f$ = freezing point constant of water = $1.86^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

$w_2$ = mass of solute (ethylene glycol) = 21.4 g

$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

$M_2$ = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

$(0-T_f)^0C=1\times (1.86^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_f=-6.6^0C$

Therefore,the freezing point of the solution is $-6.6^0C$

Elevation in boiling point :

$T_b-T^b^0=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of water = $100^0C$

$k_b$ = boiling point constant of water = $0.52^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

$w_2$ = mass of solute (ethylene glycol) = 21.4 g

$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

$M_2$ = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

$(T_b-100)^0C=1\times (0.52^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_b=101.8^0C$

Thus the boiling point of the solution is $101.8^0C$

4 0

3 years ago

Why is gold foil used on sculptures

Aleonysh [2.5K]

The gold leaf (not foil) is to give a sculpture or a painting appeal. Without it, it would discolour quicker.The gold leaf can be easily removed if needed to be.

5 0

3 years ago

Read 2 more answers

Given the following equation: 2 K + Cl2 ---> 2 KCl

Ksivusya [100]

Answer:

2 moles of KCl will be produced

Explanation:

Given parameters:

Number of moles of K = 2 moles

Unknown:

Number of moles of KCl produced = ?

Solution:

To solve this problem;

Obtain a balanced chemical equation:

2K + Cl₂ → 2KCl ;

Since K is the limiting reactant, its amount will determine the extent of this reaction.

From the balanced equation;

2 moles of K will produce 2 moles of KCl

Given that 2 moles of K reacted, 2 moles of KCl will be produced

5 0

3 years ago

Group 18 noble gases are relatively inert because *

choli [55]

Answer:I believe its A. There noble gasses so there happy with there electron count!

Explanation:

3 0

3 years ago

How many molecules are in 189.5 grams of no2?

xz_007 [3.2K]

<span>NO2 weighs 46.005 grams per mol. There are 6.02x10^23 molecules in a mol. In the given sample of 189.5 grams, there are 4.12 mols. This means that there are 2.48x10^24 molecules of NO2 in the given sample.</span>

5 0

2 years ago