The electric potential energy of the charge is reduced because it decreases with increase in the distance between charges.
<h3>What is electric potential energy?</h3>
Electric potential energy can be defined as the energy needed to move a charge against an electric field.
It is calculated using the formula;
U = Kq1 q2 ÷ r
Where Q = electric potential energy
k = Coulombs constant
q1 and q2 = charges
r = distance of separation
Electric potential energy is inversely proportional to the distance of separation of the charges.
If the distance of the charges changes from 3mm to 6mm, then the electric potential energy of the charges is reduced because it decreases with increase in the distance of the charges.
Therefore, the electric potential energy of the charge is reduced because it decreases with increase in the distance between charges.
Learn more about electric potential energy here:
brainly.com/question/14812976
#SPJ1
Vector resolution will be used to answer this question as the boat's velocity will have two components, one allowing it to travel across the river and the other taking it downstream.
Answer:
Q2: a) make sure the sugar sample used is constant
b) conduct the experiment twice and use the average
c) the type of container used
Q3: a) out of the three, icing sugar dissolves the fastest
b) substances dissolves faster in warmer waters
Q4: molecules in warmer waters moves at a greater speed than in colder waters, having more kinetic energy and colliding with the solute more frequently. More energy is then transferred to the solute molecules to break their bonds, making them dissolve faster.
at 2.304×10⁹m the electric field magnitude equal to 2.50 nc.
electric field due to a long uniformly charged wire is given as,
E= 2kλ/r
where,
k is a constant
λ is uniform charge density
r is the distance from the wire
λ = 3.20 × 10⁻¹⁰C/m
k= 9×10⁹
therefore r = 2kλ/E
on substituting value we get,
r= 2.304×10⁹m
learn more about electric field due to a uniformly charged wire here:
brainly.com/question/28166144
#SPJ4
