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Kryger [21]
3 years ago
12

Question 2 - If Juan starts out at 10m/s, and in 15 s speeds up to 60 m/s, what is his acceleration?

Physics
1 answer:
34kurt3 years ago
5 0

Answer:

B) 3.33 m/s²

Explanation:

Given that,

The initial velocity of Juan, u = 10 m/s

Final velocity of Juan,  v = 60 m/s

Time taken, t = 15 s

The acceleration is given by the relation

                          a = v-u/t  m/s²

Substituting in the above equation

                           a = 60 - 10 / 15

                           a = 3.33 m/s²

Hence, the acceleration of the Juan is, a = 3.33 m/s²

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Ahat [919]

Answer:

31.321 rad/s

Explanation:

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P=\dfrac{F}{A}=\rho gL\\\Rightarrow \dfrac{0.01A\rho\omega^2L}{A}=\rho gL\\\Rightarrow 0.01\omega^2=g\\\Rightarrow \omega^2=\dfrac{g}{0.01}\\\Rightarrow \omega=\sqrt{\dfrac{g}{0.01}}\\\Rightarrow \omega=\sqrt{\dfrac{9.81}{0.01}}\\\Rightarrow \omega=31.321\ rad/s

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3 years ago
An elevator motor provides 45.0 kW of power while lifting an elevator 35.0 m. If the elevator contains seven passengers each wit
mylen [45]

Find how much work ∆<em>W</em> is done by the motor in lifting the elevator:

<em>P</em> = ∆<em>W</em> / ∆<em>t</em>

where

• <em>P</em> = 45.0 kW = power provided by the motor

• ∆<em>W</em> = work done

• ∆<em>t</em> = 20.0 s = duration of time

Solve for ∆<em>W</em> :

∆<em>W</em> = <em>P</em> ∆<em>t</em> = (45.0 kW) (20.0 s) = 900 kJ

In other words, it requires 900 kJ of energy to lift the elevator and its passengers. The combined mass of the system is <em>M</em> = (<em>m</em> + 490.0) kg, where <em>m</em> is the mass of the elevator alone. Then

∆<em>W</em> = <em>M</em> <em>g h</em>

where

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• <em>h</em> = 35.0 m = distance covered by the elevator

Solve for <em>M</em>, then for <em>m</em> :

<em>M</em> = ∆<em>W</em> / (<em>g h</em>) = (900 kJ) / ((9.80 m/s²) (35.0 m)) ≈ 2623.91 kg

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Answer: The yellow layer is definitely older than the red layer

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