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melomori [17]
3 years ago
11

Lana does her homework as soon as she can after class, but she still doesn't undertand everything she suppose to learn. what cou

ld Lana do to get more out of her hhomework

Physics
2 answers:
Lilit [14]3 years ago
7 0
I added a screenshot with the complete question

<span><u><em>Answer:</em></u>
D. Ask her instructor questions about it the next day

<u><em>Explanation:</em></u>
We are given that Lana doesn't understand everything she's supposed to learn from the homework.

<u>Let's check the options:</u>
<u>1- start working on it eve earlier</u>
We know that she works on the homework as soon as she can. Working on it even earlier will not help her understand the difficult parts

<u>2- put it off until she's ready to work on it</u>
This is not the best option as it wont help her understand difficult parts. On the contrary, she might lose the time she has to practice the parts she understands and gain as much knowledge as possible

<u>3- Only work on it directly before going to class.</u>
this is the same as option 2. She might not even be able to finish it before the class

<u>4- Ask her instructor questions about it the next day</u>
This is the best solution as it will help her recap what she needs to learn and understand any difficult concepts as soon as possible which will help optimize her benefits

Hope this helps :)</span>

Ray Of Light [21]3 years ago
4 0

Explanation:

Since Lana is unable to understand everything while doing her homework it means that she has doubts about some of the topics given in her homework.

Therefore, in that case she should take the help of her teacher or instructor the very next day because her doubts are new and she should consult about then as soon as possible.

Thus, by doing so she can clear her doubts on time.

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5 0
3 years ago
A hammer exerts 49.8 N of force on the head (r=0.00510 m) of a nail. How much pressure does it exert on the nail?
Kisachek [45]

Answer:

609547.12 Pa ≈ 6.10×10^5 Pa

Explanation:

Step 1:

Data obtained from the question. This include the following:

Force (F) = 49.8 N

Radius (r) = 0.00510 m

Pressure (P) =..?

Step 2:

Determination of the area of the head of the nail.

The head of a nail is circular in nature. Therefore, the area is given by:

Area (A) = πr²

With the above formula we can obtain the area as follow:

Radius (r) = 0.00510 m

Area (A) =?

A = πr²

A = π x (0.00510)²

A = 8.17×10^-5 m²

Therefore the area of the head of the nail is 8.17×10^-5 m²

Step 3:

Determination of the pressure exerted by the hammer.

This is illustrated below:

Force (F) = 49.8 N

Area (A) = 8.17×10^-5 m²

Pressure (P) =..?

Pressure (P) = Force (F) /Area (A)

P = F/A

P = 49.8/8.17×10^-5

P = 609547.12 N/m²

Now, we shall convert 609547.12 N/m² to Pa.

1 N/m² = 1 Pa

Therefore, 609547.12 N/m² = 609547.12 Pa.

Therefore, the pressure exerted by the hammer on the nail is 609547.12 Pa or 6.10×10^5 Pa

8 0
4 years ago
A particle (m = 4.3 × 10^-28 kg) starting from rest, experiences an acceleration of 2.4 × 10^7 m/s^2 for 5.0 s. What is its de B
Novay_Z [31]

Answer:

Wavelength, \lambda=1.28\times 10^{-14}\ m

Explanation:

Given that,

Mass of the particle, m=4.3\times 10^{-28}\ kg

Acceleration of the particle, a=2.4\times 10^7\ m/s^2

Time, t = 5 s

It starts from rest, u = 0

The De Broglie wavelength is given by :

\lambda=\dfrac{h}{mv}

v = a × t

\lambda=\dfrac{h}{mat}

\lambda=\dfrac{6.67\times 10^{-34}}{4.3\times 10^{-28}\times 2.4\times 10^7\times 5}

\lambda=1.28\times 10^{-14}\ m

Hence, this is the required solution.

4 0
3 years ago
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