Lana does her homework as soon as she can after class, but she still doesn't undertand everything she suppose to learn. what cou
ld Lana do to get more out of her hhomework
2 answers:
I added a screenshot with the complete question
<span><u><em>Answer:</em></u>
D. Ask her instructor questions about it the next day
<u><em>Explanation:</em></u>
We are given that Lana doesn't understand everything she's supposed to learn from the homework.
<u>Let's check the options:</u>
<u>1- start working on it eve earlier</u>
We know that she works on the homework as soon as she can. Working on it even earlier will not help her understand the difficult parts
<u>2- put it off until she's ready to work on it</u>
This is not the best option as it wont help her understand difficult parts. On the contrary, she might lose the time she has to practice the parts she understands and gain as much knowledge as possible
<u>3- Only work on it directly before going to class.</u>
this is the same as option 2. She might not even be able to finish it before the class
<u>4- Ask her instructor questions about it the next day</u>
This is the best solution as it will help her recap what she needs to learn and understand any difficult concepts as soon as possible which will help optimize her benefits
Hope this helps :)</span>
<span><u><em>Answer:</em></u>
D. Ask her instructor questions about it the next day
<u><em>Explanation:</em></u>
We are given that Lana doesn't understand everything she's supposed to learn from the homework.
<u>Let's check the options:</u>
<u>1- start working on it eve earlier</u>
We know that she works on the homework as soon as she can. Working on it even earlier will not help her understand the difficult parts
<u>2- put it off until she's ready to work on it</u>
This is not the best option as it wont help her understand difficult parts. On the contrary, she might lose the time she has to practice the parts she understands and gain as much knowledge as possible
<u>3- Only work on it directly before going to class.</u>
this is the same as option 2. She might not even be able to finish it before the class
<u>4- Ask her instructor questions about it the next day</u>
This is the best solution as it will help her recap what she needs to learn and understand any difficult concepts as soon as possible which will help optimize her benefits
Hope this helps :)</span>
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Answer:
4.2 x 10⁷N
Explanation:
Given parameters:
Charge on ball:
q₁ = 3C
q₂ = 14C
Distance between balls = 9000m
Unknown:
Force acting on the two balls
Solution:
The force experienced by the two charges is given by coulombs law. It is mathematically expressed as;
F =
where k = 9 x 10⁹Nm²/C²
q is the charges
r is the distance
Input the variables and solve;
F = = 4.2 x 10⁷N
The figure shows the arrangement of system
The velocity of boat can be resolved in to two
Horizontal component = vcos θ = 2.50 cos 45 = 1.768 m/s
Vertical component = vsin θ = 2.50 sin 45 = 1.768 m/s
Due to horizontal component the boat arrive arrives upstream,
Total horizontal velocity = 1.768 - Vr, where Vr is the velocity of river.
Total time taken to cross the river = width of river/ Vertical component of velocity
t = 285/1.768 = 161.20 seconds
So 118 meter is traveled at a velocity of 1.768-Vr in 161.20 seconds
That is 118 = (1.768-Vr)*161.20
1.768 - Vr =0.732
Vr = 1.036 m/s
So velocity of river flow =1.036 m/s
