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Amanda [17]
3 years ago
5

A rod 14.0 cm long is uniformly charged and has a total charge of 222.0 mc. determine (a) the magnitude and (b) the direction of

the electric field along the axis of the rod at a point 36.0 cm from its center
Physics
1 answer:
Yuri [45]3 years ago
6 0

Electric field due to a charged rod along its axis is given by

E = \frac{kQ}{(L+r)(r)}

here we know that

L = 14 cm

r = distance from end of rod

r = 36 - 7 = 29 cm

Q = 222 mC

now we will have

E = \frac{(9 \times 10^9)(222 \times 10^{-3})}{(0.29)(0.43)}

E = 1.6 \times 10^{10} N/C

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A force of 62 N acts on a 35 kg object for 10.0s. What is the objects change in momentum?
Makovka662 [10]

Answer:

Δp = 620 N.s

Explanation:

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       F = \frac{\Delta p}{\Delta t}  (1)

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7 0
3 years ago
Is there a point between a 10 nc charge and a 20 nc charge at which the electric field is zero?
Komok [63]

Let 10 nC and 20 nC charge is placed at "d" distance

now let say we will have a point at distance "x" from 10 nC at which electric field will be zero

now we will have

E_1 = E_2

\frac{kq_1}{x^2} = \frac{kq_2}{(d-x)^2}

now plug in all data

\frac{k(10 nC)}{x^2} = \frac{k(20 nC)}{(d-x)^2}

\frac{10}{x^2} = \frac{20}{(d-x)^2}

square root both sides

\frac{1}{x} = \frac{\sqrt2}{d - x}

d - x = \sqrt2 x

d = x(1 + \sqrt2)

x = \frac{d}{1 + \sqrt2}

so yes there will exist a point between 10 nC and 20 nC charge at which electric field will be zero

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3 years ago
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