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lutik1710 [3]
3 years ago
6

Assuming you are in the Northern Hemisphere, how would you expect the location of the Sun in your local sky at noon to differ fr

om season to season?
Physics
1 answer:
topjm [15]3 years ago
3 0

Answer:

It should be higher during the summer.

Explanation:

Assuming that youlive in the Northern Hemisphere, the sun's location through the season from winter to summer at noon, should be different. The sun would be observed at a higher position over the horizon in the summer season than it is in the winter season. The reasons are equinoxes, solstices and the ecliptic circle.

I hope this answer helps.

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All of the following are environmental factors that affect human development except _____.
MrRa [10]

Answer:

The answer would be....

Explanation:

Chromosomes.

5 0
3 years ago
What is role of skin in balancing body temperature during strenous excervise
trapecia [35]

Answer:

The skin releases sweat

Explanation:

The body temperature is necessary to maintain homeostasis. Skin  controls body temperature by sweating when it is too heated.

3 0
3 years ago
Why do sex cells contain only half the number of chromosomes needed for offspring? Explain
Bogdan [553]

Answer:

None, egg cells don't have chromosomes. No, sex cells do have chromosomes. Meiosis reduces chromosome number so that sex cells (eggs and sperm) have a half set of chromosomes–one homolog of each pair. This is the haploid number.

3 0
3 years ago
The magnetic field strength at the north pole of a 2.0-cmcm-diameter, 8-cmcm-long Alnico magnet is 0.10 TT. To produce the same
horrorfan [7]

Answer:

2653 turns

Explanation:

We are given that

Diameter,d=2 cm

Length of magnet,l=8 cm=8\times 10^{-2} m

1m=100 cm

Magnetic field,B=0.1 T

Current,I=2.4 A

We are given that

Magnetic field of solenoid and magnetic are same and size of both solenoid and magnetic are also same.

Length of solenoid=8\times 10^{-2} m

Magnetic field of solenoid

B=\frac{\mu_0NI}{l}

Using the formula

0.1=\frac{4\pi\times 10^{-7}\times 2.4\times N}{8\times 10^{-2}}

Where \mu_0=4\pi\times 10^{-7}

N=\frac{0.1\times 8\times 10^{-2}}{4\pi\times 10^{-7}\times 2.4}=2653 turns

6 0
2 years ago
A horizontal force of 92.7 N is applied to a 40.5 kg crate on a rough, level surface. If the crate accelerates at 1.13 m/s2, wha
lord [1]

Answer:

The value is F_f =  46.935 \  N

Explanation:

From the question we are told that

    The  magnitude of the horizontal force is F  =  92.7 \  N

     The mass of the crate is  m  =  40.5 \  kg

     The acceleration of the crate is  a =  1.13 \ m/s

Generally the net force acting on the crate is mathematically represented as

       F_{net} =  F -  F_f =  ma

Here F_f is force of kinetic friction (in N) acting on the crate

      So  

            92.7  -  F_f =  40.5 * 1.13

=>         F_f =  46.935 \  N

5 0
3 years ago
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