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Answer: 7918 J
Explanation:
We are assuming that the floor (field) is completely horizontal since there's no information about that in the statement.
We are going to use the following formula:
Where:
º
Then, by substituting we have:
It d bro it’s d bro it’s d
The approximate orbital period of this star is 13 years.
<h3>What is Kepler's third law?</h3>
The square of a planet's period of revolution around the sun in an elliptical orbit is directly proportional to the cube of its semi-major axis, states Kepler's law of periods.
T² ∝ a³
The time it takes for one rotation to complete depends on how closely the planet orbits the sun. With the use of the equations for Newton's theories of motion and gravitation, Kepler's third law assumes a more comprehensive shape:
P² = 4π² /[G(M₁+ M₂)] × a³
where M₁ and M₂ are the two circling objects' respective masses in solar masses.
Learn more about Kepler's third law here:
brainly.com/question/1608361
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Answer:
the work that must be done to stop the hoop is 2.662 J
Explanation:
Given;
mass of the hoop, m = 110 kg
speed of the center mass, v = 0.22 m/s
The work that must be done to stop the hoop is equal to the change in the kinetic energy of the hoop;
W = ΔK.E
W = ¹/₂mv²
W = ¹/₂ x 110 x 0.22²
W = 2.662 J
Therefore, the work that must be done to stop the hoop is 2.662 J
