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11111nata11111 [884]
3 years ago
13

Suppose you are taking a walk one day when you see a tree branch snap at its base and begin to rotate downward with the break ne

ar the trunk of the tree as a pivot point. You estimate the length of the branch to be about 3 meters. Estimate the initial angular acceleration of the branch in rad/s2. Can you estimate the mass of the tree branch from this information? Why or why not?

Physics
1 answer:
Naya [18.7K]3 years ago
6 0

Answer:

α = 3.27 rad/s²

No

Explanation:

Given that

 L= 3 m

Lets take mass of tree = m kg

The torque to mass m =  m g .L

The mass moment of inertia of tree ,I

I = mL² kg.m²

We know that

τ = I α

 m g .L = mL² .α

α= g/L

Now by putting the value

\alpha =\dfrac{ 9.81}{ 3}\ rad/s^2

α = 3.27 rad/s²

No we can find the mass of the from the above information because angular acceleration is not depend on the mass of tree.

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If the potential due to a point charge is 490 V at a distance of 10 m, what are the sign and magnitude of the charge?
uysha [10]

Answer:

+5.4×10⁻⁷ C

Explanation:

Electric potential: This can be defined as the work done in bringing a unit charge from infinity to that point against the action of the field. The S.I unit of potential is volt (V)

The formula for potential is

V = kq/r............................ Equation 1

Where V = electric potential, k = proportionality constant, q = charge, r = distance.

making q the subject of the equation,

q = Vr/k............................ Equation 2

Given: V = 490 V, r = 10 m,

Constant: k = 9×10⁹ Nm²/C²

Substitute into equation 2

q = 490(10)/(9×10⁹)

q = 5.4×10⁻⁷ C

q = +5.4×10⁻⁷ C

Hence the charge is +5.4×10⁻⁷ C

7 0
3 years ago
If mechanical energy is conserved, then a pendulum that has a potential energy of 20 J at its highest point and 0.5 J at its low
liraira [26]
At the highest point: kinetic energy is 0 due to the speed  is 0

So the total mechanical energy is 20

Assume no frictions present, then the mechanical energy is conserved

So at the lowest point, kinetic energy = mechanical energy - potential energy

Answer will be 20 - 0.5 = 19.5 J
4 0
4 years ago
collision occurs betweena 2 kg particle traveling with velocity and a 4 kg particle traveling with velocity. what is the magnitu
anzhelika [568]

Answer:

metre per seconds

Explanation:

because velocity = distance ÷ time

4 0
3 years ago
If 1.34 ✕ 1020 electrons move through a pocket calculator during a full day's operation, how many coulombs of charge moved throu
ioda

Given :

Number of operations move through a pocket calculator during a full day's operation , n=1.34 \times 10^{20} .

To Find :

How many coulombs of charge moved through it .

Solution :

We know , charge in  one electron is :

e^-=-1.6\times 10^{-19}\ coulombs

So , charge on n electron is :

C=e^-\times n\\C=-1.6\times 10^{-19}\times 1.34\times 10^{20} \ C\\C=-21.44\ C

Therefore , -21.44 coulombs of charge is moved through it .

Hence , this is the required solution .

3 0
3 years ago
Um móvel realiza movimento retilíneo uniformemente
Alona [7]
B is the correct answer hope that helped
8 0
3 years ago
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