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11111nata11111 [884]
3 years ago
13

Suppose you are taking a walk one day when you see a tree branch snap at its base and begin to rotate downward with the break ne

ar the trunk of the tree as a pivot point. You estimate the length of the branch to be about 3 meters. Estimate the initial angular acceleration of the branch in rad/s2. Can you estimate the mass of the tree branch from this information? Why or why not?

Physics
1 answer:
Naya [18.7K]3 years ago
6 0

Answer:

α = 3.27 rad/s²

No

Explanation:

Given that

 L= 3 m

Lets take mass of tree = m kg

The torque to mass m =  m g .L

The mass moment of inertia of tree ,I

I = mL² kg.m²

We know that

τ = I α

 m g .L = mL² .α

α= g/L

Now by putting the value

\alpha =\dfrac{ 9.81}{ 3}\ rad/s^2

α = 3.27 rad/s²

No we can find the mass of the from the above information because angular acceleration is not depend on the mass of tree.

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A sound wave travels in air toward the surface of a freshwater lake and enters into the water. The frequency of the sound does n
Shkiper50 [21]

Answer:

Explanation:

velocity of sound in air at 20⁰C is 343 m /s

velocity of sound in water at 20⁰C is 1481 m /s

The wavelength of the sound is 2.86 m in the air so its frequency

= 343 / 2.86 = 119.93 .

This frequency of  119.93 will remain unchanged in water .

wavelength in water = velocity in water / frequency

= 1481 / 119.93

= 12. 35 m .

7 0
2 years ago
A positively charged sphere with a charge of 8Q is separated from a negatively charged sphere -2Q by a distance r. There is an a
djverab [1.8K]

Answer:

Explanation:

For the first case , the expression for electrostatic force can be given by the following .

F = K x 8Q x 2Q / r² where k is a constant .

F = K 16 Q² / r²

When they touch , some charge is neutralized . Net charge remaining

= 8Q - 2 Q = 6 Q

Charge on each sphere = 6Q/2 = 3 Q .

Force between them

F₁ = k 3Q x 3 Q / r² = k 9 Q² / r²

F₁ / F = 9 / 16

F₁ = 9 F / 16 .

4 0
2 years ago
An airtight box has a removable lid of area 1.10 10-2 m2 and negligible weight. The box is taken up a mountain where the air pre
andrezito [222]

Answer:

F=7.7\times10^2 N

Explanation:

The magnitude of force required to pull the lid off the box by air pressure.

We know that Pressure, P= Force(F)/Area(A)

Force, F= P×A

Given: A=1.10\times10^{-2} m^2

P=7\times10^{4} Pa.

Therefore, F=7\times10^{4}\times1.10\times10^{-2}.

F=7.7\times10^2 N

4 0
3 years ago
A current is established in a gas discharge tube when a sufficiently high potential difference is applied across the two electro
pishuonlain [190]

Explanation:

It is given that the number of electrons passing through the cross-sectional area in 1 s is 3.4 \times 10^{18}. Also, we know that charge on an electron is -1.60 \times 10^{-19} C, then negative charge crossing to the left per second is  as follows.

         I- = 3.4 \times 10^{18} electrons \times -1.6 x 10^{-19} C/electrons

         I- = 0.544 A

As it is given that the number of protons crossing per second is 1.4 \times 10^{18}, as the charge on the proton is +1.60 \times 10^{-19} C, then positive charge crossing to the right per second is calculated as follows.

          I+ = 1.4 \times 10^{18} electrons \times 1.6 \times 10^{-19} electrons/C

            I+ = 0.224 A

          I = l I+ l + l I- l

So,    I = 0.544 + 0.224

            = 0.768 A

Thus, we can conclude that the current in given hydrogen discharge tube is 0.768 A.

8 0
2 years ago
18°C = _____ <br>-255 K<br> 0 K <br>18 K <br>291 K
Nadya [2.5K]

18°C answer is 291 k

hope it help

4 0
3 years ago
Read 2 more answers
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