When Isabella pushes a box of mass 5.25 kilograms with a force of 15.7 newtons, it accelerates by a rate of 2.50 meters/second2.
2 answers:
Answer:
The coefficient of friction is 0.05
Explanation:
Given that,
When Isabella pushes a box of mass 5.25 kilograms with a force of 15.7 newtons.
It accelerates by a rate of 2.50 m/s²
Let coefficient of friction be μ
Force (F) = 15.7 N
Acceleration (a) = 2.5 m/s²
Mass (m) = 5.25 kg
Gravity (g) = 9.8 m/s²
Balanced equation of box to move
F - μmg = ma
15.7 - μ(5.25)(9.8) = (5.25)(2.50)
Hence, The coefficient of friction is 0.05
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Answer:
The average current I supplied to the cars motor is 0.225 Amperes.
Explanation:
The mass of the toy car is given as, m = 0.6 kg
The toy car operates at a steady speed of, v = 3.43 m/s.
It achieves the steady speed after a time, t = 5.69 seconds.
The total kinetic energy of the car is given by,
E =
= 0.5 × 0.6 ×
= 3.53 Joules
Since the efficiency of the motor is 30.6% = 0.306
The electrical energy equivalent is supplied to motor = .
The electrical energy is given by P × t = I × V × t = 11.54 Joules
P is the electric power where P = I × V where V is the voltage of the cell and is the average current, I.
Therefore we can write I × 9 × 5.69 = 11.54 Joules.
So the average current I = = 0.225 Amperes.