Question

When Isabella pushes a box of mass 5.25 kilograms with a force of 15.7 newtons, it accelerates by a rate of 2.50 meters/second2. What is the force due to friction in this scenario?

Answer 1

Answer:

The coefficient of friction is 0.05

Explanation:

Given that,

When Isabella pushes a box of mass 5.25 kilograms with a force of 15.7 newtons.

It accelerates by a rate of 2.50 m/s²

Let coefficient of friction be μ

Force (F) = 15.7 N

Acceleration (a) = 2.5 m/s²

Mass (m) = 5.25 kg

Gravity (g) = 9.8 m/s²

Balanced equation of box to move

F - μmg = ma

15.7 - μ(5.25)(9.8) = (5.25)(2.50)

$\mu = \dfrac{15.7-5.25\cdot 2.5}{5.25\cdot 9.8}$

$\mu = 0.05$

Hence, The coefficient of friction is 0.05

Answer 2

Resultant force on the box = mass x acceleration

Sigma F = ma

Fr: friction force

15.7 - Fr = 5.25 x 2.5

15.7 - Fr = 13.125

Fr = 15.7 - 13.125 = 2.575 N