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MariettaO [177]
3 years ago
12

A child with mass of 25 kg gets into a toy car with mass of 80 kg on a playground, causing it to sink on its springs (with effec

tive spring constant 791 N/m). An adult walks by and gives the top of the car a shove, causing it to undergo oscillations with amplitude 31 cm in the vertical direction. Assuming the oscillations are simple harmonic, what is the frequency of the oscillations?
Physics
1 answer:
Bess [88]3 years ago
4 0

Answer:

The frequency of the oscillation is 0.9Hz

Explanation:

This problem bothers on simple harmonic motion of a spring

Given data

Mass of the child m= 25kg

Spring constant k=791 N/m

Amplitude a= 31cm

But the period of the motion as a result of the adults sholve is expressed as

T=2π√m/k

T=2*3.142√25/791

T=6.284√0.031

T=6.284*0.176

T=1.11 sec

But frequency F=1/T

F=1/1.11

F=0.9Hz

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The name of C (S) + o2 (g) CO2 (g)
USPshnik [31]

Answer:

carbon + oxygen → carbon dioxide

6 0
3 years ago
Strontium−90 is one of the products of the fission of uranium−235. This strontium isotope is radioactive, with a half-life of 28
Ludmilka [50]

Answer : The time passed in years is 20.7 years.

Explanation :

Half-life = 28.1 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{28.1\text{ years}}

k=2.47\times 10^{-2}\text{ years}^{-1}

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 2.47\times 10^{-2}\text{ years}^{-1}

t = time passed by the sample  = ?

a = initial amount of the reactant  = 1.00 g

a - x = amount left after decay process = 0.600 g

Now put all the given values in above equation, we get

t=\frac{2.303}{2.47\times 10^{-2}}\log\frac{1.00}{0.600}

t=20.7\text{ years}

Therefore, the time passed in years is 20.7 years.

8 0
3 years ago
IF THERE ARE ONLY 118 ELEMENTS, HOW DO YOU ACCOUNT FOR THE MANY MILLIONS OF THINGS THAT WE HAVE IN OUR UNIVERSE?
bogdanovich [222]

Answer:

theres only 118 elements that are discovered. now that they're the only ones out there

Explanation:

3 0
2 years ago
Plz solve completely
tiny-mole [99]

Answer:

Explanation:

wouldnt it just be x=0 sorry if im

wrong

6 0
3 years ago
A voltmeter and an ammeter are used to respectively monitor the voltage across and the current through a resistor connected to a
dsp73

Answer:

(a) 95 volt

(b)  134.33 volt

(c) 10.746 volt

(d) Average delivered power is 722 watt  

Explanation:

We have given value of resistance R = 12.5 ohm

Current in the ammeter i = 7.60 A

(a) Rms voltage in the resistor V=iR=7.6\times 12.5=95volt

(b) We know that rms voltage is given by v_r=\frac{v_m}{\sqrt{2}}

v_m=\sqrt{2}v_r=1.414\times 95=134.33volt

So peak voltage will be equal to 134.33 volt

(c) Maximum current is equal to i_m=\sqrt{2}i_r=1.414\times 7.6=10.746A

(d) Average power delivered in the resistor is equal to

P = VI

So P=95\times 7.6=722watt

7 0
3 years ago
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