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MariettaO [177]

3 years ago

12

A child with mass of 25 kg gets into a toy car with mass of 80 kg on a playground, causing it to sink on its springs (with effec

tive spring constant 791 N/m). An adult walks by and gives the top of the car a shove, causing it to undergo oscillations with amplitude 31 cm in the vertical direction. Assuming the oscillations are simple harmonic, what is the frequency of the oscillations?

1 answer:

Bess [88]3 years ago

4 0

Answer:

The frequency of the oscillation is 0.9Hz

Explanation:

This problem bothers on simple harmonic motion of a spring

Given data

Mass of the child m= 25kg

Spring constant k=791 N/m

Amplitude a= 31cm

But the period of the motion as a result of the adults sholve is expressed as

T=2π√m/k

T=2*3.142√25/791

T=6.284√0.031

T=6.284*0.176

T=1.11 sec

But frequency F=1/T

F=1/1.11

F=0.9Hz

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A 1.83 kg book is placed on a flat desk. Suppose the coefficient of static friction between the book and the desk is 0.442 and t

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Answer:7.92 N

Explanation:

Given

mass of book $m=1.83\ kg$

coefficient of static friction $\mu _s=0.442$

coefficient of kinetic friction $\mu _k=0.240$

To move the book, one need to overcome the static friction

Static friction $F_s=\mu _sN$

$F_s=\mu _s\times 1.83\times 9.8$

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$F_s=7.92\ N$

After overcoming the Static friction , Force needed to move the block is

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3 years ago

A basketball with mass of 0.8 kg is moving to the right with velocity 6 m/s and hits a volleyball with mass of 0.6 kg that stays

IceJOKER [234]

Answer:

26.67 m/s

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From the law of conservation of linear momentum, the initial sum of momentum equals the final sum.

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Initial momentum

The initial momentum will be that of basketball and volleyball, Since basketball is initially at rest, its initial velocity is zero

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After Moseley's discovery in 1913, the periodic law stated that physical and chemical properties tend to repeat periodically whe

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Answer:

Option B

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The correct answer is Option B.

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Do black holes have an internal structure? If so, how might the internal structure be probed?

oksian1 [2.3K]

Answer:

no

Explanation:

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5 0

3 years ago

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A 20.0-kg rock is sliding on a rough, horizontal surface at 8.00 m/s and eventually stops due to friction. The coefficient of ki

Neporo4naja [7]

Answer:

$a = -1.961\,\frac{m}{s^{2}}$ , $s = 16.318\,m$ , $t = 4.079\,s$

Explanation:

The equations of equilibrium for the rock are:

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$\Sigma F_{y} = N - m\cdot g = 0$

After some algebraic handling, the following expression is found:

$-\mu_{k}\cdot m \cdot g = m \cdot a$

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$a = -1.961\,\frac{m}{s^{2}}$

The distance travelled by the rock before stopping is:

$s = \frac{(0\,\frac{m}{s} )^{2}-(8\,\frac{m}{s} )^{2}}{2\cdot (-1.961\,\frac{m}{s^{2}} )}$

$s = 16.318\,m$

And the time is:

$t = \frac{0\,\frac{m}{s}-8\,\frac{m}{s}}{(-1.961\,\frac{m}{s^{2}} )}$

$t = 4.079\,s$

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3 years ago

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