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denis23 [38]
3 years ago
9

solve this system of linear equations. separate the x- and y- values with a comma. 6x +5y=-19 12x-8y=52

Mathematics
1 answer:
Ymorist [56]3 years ago
8 0

ANSWER

The solution is

(x,y)=(1,-5)

EXPLANATION

The equations are:

1st equation: 6x +5y=-19

2nd equation: 12x-8y=52

Multiply the first equation by 2:

3rd equation: 12x +10y=-38

Subtracy the 2nd equation from the 3rd equations.

12x-12x+10y--8y=-38-52

18y=-90

Divide both sides by 18.

y=-5

Put y=-5 into any of the equations and solve for x.

Preferably, the first equation will do.

6x +5(-5)=-19

6x -25=-19

6x=25-19

6x=6

x=1

The solution is

(x,y)=(1,-5)

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Which of the following is the number 5.03 x 10-5 written in standard form?
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Step-by-step explanation:

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proving:

503,000 > 10

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=5.03 ×10-5

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Evaluate (7^2))^-2/7^-4
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6 0
2 years ago
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The minimum weekly commission earned to be a STAR sales person is $9000. If Sandra receives a 12% commission on the sale of all
katovenus [111]

Answer:

numbers\ of\ cars \geq \frac{75000}{price\ of\ the\ car}

Step-by-step explanation:

Hello, I can help you with this

Step 1

define

The minimum weekly commission earned to be a STAR sales person is $9000, let's name this value as M

if Sandra receives a 12% commisions of the sale of all cars, then that 12% must be equal or higher than 9000 in order to become a STAR sales person

Step 2

using a rule of three find the 100%

if

12% ⇔ $9000

then

100% ⇔x

the ratio is

\frac{12}{9000}=\frac{100}{x}\\

Now, solve for x

\frac{12}{9000}=\frac{100}{x}\\\\\frac{12*x}{9000}=\frac{100}\\\\{12x}=9000*100\\\\12x=900000\\x=\frac{900000}{12}\\ x=75000\\

so, Sandra must sell a minimun of $75000

Now, to give a response, we need to asume a only price for every car(p).

now, in matemathical terms.

the minimun number of cars she must to sell is

minum number of cars sandra has to sell to become a STAR sales person

is \frac{75000}{price\ of\ the\ car} \\

\frac{75000}{price\ of\ the\ car} \\

now, price of the car* number of the car = 75000

where

numbers\ of\ cars \geq \frac{75000}{price\ of\ the\ car}

Have a nice day

6 0
3 years ago
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