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Snezhnost [94]
3 years ago
7

36.25= 45.5% of ____

Mathematics
1 answer:
aev [14]3 years ago
7 0

Answer:

36.25 is equal to the 45.5% of 79.67

Step-by-step explanation:

To solve this you just have to find the value that represents the 100%.

To do this, you can use the Rule of Three that allows you to solve problems of proportions.

In this case, you know that the 45.5% of the magnitude <em>X </em>is 36.25, now you have to find the value which corresponds to the 100%.  

Mathematically it will be:

\frac{X}{36.25} =\frac{100}{45.5}

Then you have to solve the equation to find <em>X</em>:

X=\frac{100}{45.5}*36.25

And finally, the answer is:

X=79.67

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Sam read 20% of the book on Monday and 0.2 of the book on Tuesday. If he read 50% of the remainder on Wednesday and still had 36
KonstantinChe [14]
Okay first you need to convert 0.2 to a percentage which would be 20% then 20% + 20% = 40% then it says he read 50%, 50% of 36 means that you have to multiply 36 two times to get, 72 then you do 72 * 40% = 28.8 = 29 + 72 = 101 pages in all then 101- 40%= 60.6 is how many pages were read on Monday and Tuesday.
8 0
3 years ago
Find the scale factor of the smaller figure to the larger figure
guapka [62]

Answer:

#9: 1.2

#10: 1.25

Step-by-step explanation:

To find the scale factor of the smaller figure to the larger figure, we're going to be dividing the measurements of corresponding edges.

\frac{larger figure}{smaller figure}

If you wanted to find the scale factor of the larger figure to the smaller figure, you'd do: \frac{smaller figure}{larger figure}

Question #9:

Left edges: \frac{larger figure}{smaller figure} ⇒ \frac{24}{20} = 1.2

Bottom edges: \frac{larger figure}{smaller figure} ⇒ \frac{30}{25} = 1.2

<em>(You should get the same number as long as the figures are similar.)</em>

<em />

Question #10:

Bottom edges: \frac{larger figure}{smaller figure} ⇒ \frac{30}{24} = 1.25

<em>(There are no corresponding edges with measurements that we can compare.)</em>

<em />

~Hope this helps!~

4 0
3 years ago
Why is it important to be able to solve for variables in equations?
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2 years ago
An exam consists of 50 multiple choice questions. Based on how much you studied, for any given question, you think you have a pr
astraxan [27]

Answer: (a) mean = 32.00

(b)Standard error = 0.068

It is expected that the shape will approximately large because n is large.

(c)P(z< 0.60)= 0

Step-by-step explanation:

a. Mean = nP= 0.64× 50 = 32.00(2dp)

P= 0.64

b. Standard error = √ p(1-p)/n

= √0.64(0.36)/50

= 0.068(3dp)

c. Using P(Z<X - U/S)

Where S = standard error

U = mean = 0.64

(c)P(z< 0.60)=

= P( z< 0.60 - 0.64/0.068)

= P( z < -5.88)

= 0.

3 0
3 years ago
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