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eduard
3 years ago
8

If the diameter of a circle is 25 inches, what is the radius of the circle?

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
8 0
Hello there, and thank you for posting your question here on brainly.

The diameter of a circle is how long it is from the left side of the circle to the right side.

The radius of a circle is the length of either the left or the right side to the middle.

So, the radius is half of a radius.

You can divide the known diameter by 2 to get your answer.

Its diameter is 25.

Divide 25 by 2.

25 / 2 = 12.5

Its radius is 12.5 in.

That would be answer choice A.

Hope this helped!! ☺♥
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<h2>The first graph in the second image is an odd function.</h2>

Step-by-step explanation:

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So, we have to look for those graph that has symmetrical points in opposite quadrants, I and III or II and IV.

You can observe that the first graph of the second image has this behaviour. You can see that the points are symmetrical across the origin. If you graph a line defined as y=-x, you will observe that such line acts like a mirror.

Therefore, the odd function is the first graph in the second image.

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Answer:it would be 1/16+1/4=1 mile

Step-by-step explanation:

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4 years ago
Somebody, please help me it's URGENT
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Answer:

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3 years ago
Uninhibited growth can be modeled by exponential functions other than​ A(t) ​=Upper A 0 e Superscript kt. For ​ example, if an i
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The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than A(t)=A_{0}e^{kt}. for example, if an initial population P₀ requires n units of time to triple, then the function P(t)=P_{0}(3)^{\frac{t}{n} } models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form P(t)=P_{0}(3)^{\frac{t}{n} } that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form A(t)=A_{0}e^{kt}.

Answer: a) P(t)=50(3)^{\frac{t}{30} }

              b) P(t) = 280 insects

              c) t = 74 days

             d) A(t)=50e^{0.037t}

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

P(t)=50(3)^{\frac{t}{30} }

b) In t = 47 days:

P(t)=50(3)^{\frac{t}{30} }

P(47)=50(3)^{\frac{47}{30} }

P(47)=50(3)^{1.567}

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

750=50(3)^{\frac{t}{30} }

\frac{750}{50}=(3)^{\frac{t}{30} }

(3)^{\frac{t}{n} }=15

Using the property <u>Power</u> <u>Rule</u> of logarithm:

log(3)^{\frac{t}{30} }=log15

\frac{t}{30}log(3)=log15

t=\frac{log15}{log3} .30

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

A(t)=A_{0}e^{kt}

3A_{0}=A_{0}e^{30k}

3=e^{30k}

Use Power Rule again:

ln3=ln(e^{30k})

ln3=30k

k=\frac{ln3}{30}

k = 0.037

Equation for exponential growth will be:

A(t)=50e^{0.037t}

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Answer:

The function f(x) has a vertical asymptote at x = 3

Step-by-step explanation:

We can define an asymptote as an infinite aproximation to given value, such that the value is never actually reached.

For example, in the case of the natural logarithm, it is not defined for x = 0.

Then Ln(x) has an asymptote at x = 0 that tends to negative infinity, (but never reaches it, as again, Ln(x) is not defined for x = 0)

So a vertical asymptote will be a vertical tendency at a given x-value.

In the graph is quite easy to see it, it occurs at x = 3 (the graph goes down infinitely, never actually reaching the value x = 3)

Then:

The function f(x) has a vertical asymptote at x = 3

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