Question

Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1). The triangle is translated 3 units to the left and 1 unit up. What are the coordinates of B' after the translation?
a.(1, 6)
b.(–3, 6)
c.(0, 0)
d.(3, 1)

Answer 1

The coordinates are -3 , 6

Answer 2

Answer:

b. $(-3,6)$

Step-by-step explanation:

We have been given that triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1). The triangle is translated 3 units to the left and 1 unit up.

To find the coordinates of B', we will shift x-coordinate of point B to left by 3 units and y-coordinate of point B to 1 unit up.

After the given transformation the coordinates of point B' would be:

$B(0,5)\rightarrow B'((0-3),(5+1))\rightarrow (-3,6)$

Therefore, the coordinates of point B' are $(-3,6)$ and option 'b' is the correct choice.