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Leokris [45]
3 years ago
14

What is true about all points on the y-axis in Quadrant I?

Mathematics
1 answer:
Eva8 [605]3 years ago
6 0

Answer:

All have an x-coordinate of 0.

and

All are directly above the origin.

These answers are correct

Step-by-step explanation:

i did the quiz/or/assignment

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5x + 14 = K solve for K
siniylev [52]
 Flip the equation.<span>k=<span><span>5x</span>+<span>14</span></span></span>
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On a separate piece of graph paper, graph y = -|x + 1|; then click on the graph until the correct one appears
LenKa [72]

Answer:

See picture for graph.

Step-by-step explanation:

The graph of an absolute value is a V shape function. The negative in front turns the V upside down. The (x+1) determines the x-coordinate of the vertex. The vertex will be (-1,0). See picture for the graph.

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PLEASE HELP The coefficients of the first four terms in the expansion of (a + b) ^5 are a) 1, 3, 5, 7 b) 1, 4, 6, 4 c) 1, 2, 3,
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Answer:

D is the correct answer

Step-by-step explanation:

Fifth row of Pascal pyramid is 1 , 5, 10, 10, 5 , 1

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Where n is the power

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3 years ago
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Evaluate the spherical coordinate integral
expeople1 [14]

Rewrite the equations of the given boundary lines:

<em>y</em> = -<em>x</em> + 1  ==>  <em>x</em> + <em>y</em> = 1

<em>y</em> = -<em>x</em> + 4  ==>  <em>x</em> + <em>y</em> = 4

<em>y</em> = 2<em>x</em> + 2  ==>  -2<em>x</em> + <em>y</em> = 2

<em>y</em> = 2<em>x</em> + 5  ==>  -2<em>x</em> + <em>y</em> = 5

This tells us the parallelogram in the <em>x</em>-<em>y</em> plane corresponds to the rectangle in the <em>u</em>-<em>v</em> plane with 1 ≤ <em>u</em> ≤ 4 and 2 ≤ <em>v</em> ≤ 5.

Compute the Jacobian determinant for this change of coordinates:

J=\begin{bmatrix}\frac{\partial u}{\partial x}&\frac{\partial u}{\partial y}\\\frac{\partial v}{\partial x}&\frac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}1&1\\-2&1\end{bmatrix}\implies|\det J|=3

Rewrite the integrand:

-3x+4y=-3\cdot\dfrac{u-v}3+4\cdot\dfrac{2u+v}3=\dfrac{5u+7v}3

The integral is then

\displaystyle\iint_R(-3x+4y)\,\mathrm dx\,\mathrm dy=3\iint_{R'}\frac{5u+7v}3\,\mathrm du\,\mathrm dv=\int_2^5\int_1^45u+7v\,\mathrm du\,\mathrm dv=\boxed{333}

5 0
4 years ago
A patient is ordered 60 mg/kg/day of an antibiotic to be divided in 3 doses per day. The patient weighs 60 kg. How many mg of dr
Fudgin [204]

Answer:

3600 mg of drug per day.

\text{The amount of drug per dosage}=\text{1200 mg}

Step-by-step explanation:

We have been given that a patient is ordered 60 mg/kg/day of an antibiotic.

Since the weight of the patient is 60 kg, so the dosage of drug per day would be 60 mg times 60.

\text{The dosage of drug per day}=\frac{\text{60 mg}}{\text{ kg}}\times 60\text{ kg}

\text{The dosage of drug per day}=\text{60 mg}\times 60

\text{The dosage of drug per day}=\text{3600 mg}

Therefore, the patient should receive 3600 mg of drug per day.

Since the patient gets 3 doses per day, so dosage of drug per dosage would be amount of drug per day divided by 3.

\text{The amount of drug per dosage}=\frac{\text{3600 mg}}{3}

\text{The amount of drug per dosage}=\text{1200 mg}

Therefore, the amount of drug per dosage would be 1200 mg.

3 0
4 years ago
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