What is true about all points on the y-axis in Quadrant I?
1 answer:
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Answer:
See picture for graph.
Step-by-step explanation:
The graph of an absolute value is a V shape function. The negative in front turns the V upside down. The (x+1) determines the x-coordinate of the vertex. The vertex will be (-1,0). See picture for the graph.
Rewrite the equations of the given boundary lines:
<em>y</em> = -<em>x</em> + 1 ==> <em>x</em> + <em>y</em> = 1
<em>y</em> = -<em>x</em> + 4 ==> <em>x</em> + <em>y</em> = 4
<em>y</em> = 2<em>x</em> + 2 ==> -2<em>x</em> + <em>y</em> = 2
<em>y</em> = 2<em>x</em> + 5 ==> -2<em>x</em> + <em>y</em> = 5
This tells us the parallelogram in the <em>x</em>-<em>y</em> plane corresponds to the rectangle in the <em>u</em>-<em>v</em> plane with 1 ≤ <em>u</em> ≤ 4 and 2 ≤ <em>v</em> ≤ 5.
Compute the Jacobian determinant for this change of coordinates:
Rewrite the integrand:
The integral is then
Answer:
3600 mg of drug per day.
Step-by-step explanation:
We have been given that a patient is ordered 60 mg/kg/day of an antibiotic.
Since the weight of the patient is 60 kg, so the dosage of drug per day would be 60 mg times 60.
Therefore, the patient should receive 3600 mg of drug per day.
Since the patient gets 3 doses per day, so dosage of drug per dosage would be amount of drug per day divided by 3.
Therefore, the amount of drug per dosage would be 1200 mg.